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00:00:07
Hello Hello guys My name is
00:00:10
Belousova Tatyana Gennadievna I am a
00:00:13
chemistry teacher today I continue to study
00:00:15
chemical bonds we have come to the study of
00:00:18
ionic bonds Before this we talked about the fact
00:00:21
that a bond can be covalent, this is a bond between
00:00:25
non-metals if they have the same
00:00:28
electronegativity then it will be
00:00:30
equivalent to a non-polar bond if it
00:00:33
differs slightly within the
00:00:35
difference in electronegativity of up to two
00:00:39
units, then accordingly it will be
00:00:42
Covalently Polar bond What is an ionic
00:00:45
bond, the name itself suggests this
00:00:47
bond between ions Then you need to remember
00:00:50
And what are ions Ions are charged
00:00:56
particles into which atoms pass by
00:00:59
giving up or accepting electrons Well, for
00:01:02
example, if we're talking about it's not
00:01:04
sodium, let's look at the
00:01:07
periodic table. We'll see that sodium is in the
00:01:10
first group of the main subgroup and that means
00:01:13
it has one Electron at the external level
00:01:15
that it will give up. And
00:01:17
therefore it will be and it will have a
00:01:20
dispositional charge if we
00:01:23
took for example the metal magnesium, which
00:01:25
is the closest neighbor of sodium, then
00:01:28
magnesium, accordingly, already at the outer
00:01:31
level of 2 electrons, he will also give them up
00:01:33
because for the purpose of completion it is
00:01:36
beneficial for him and, accordingly, its charge will be
00:01:39
two plus, if we take for example
00:01:41
aluminum next to magnesium, then
00:01:44
aluminum, accordingly, the charge will be 3 + Let
00:01:47
me remind you that ions with a positive
00:01:50
charge have their own special charge, they are
00:01:54
called cations and now we move on to
00:01:57
ions of a different charge, not necessarily all of them
00:02:00
and it only has a positive charge.
00:02:02
For example, if we take chlorine, chlorine
00:02:05
is in the seventh group of the main
00:02:07
group. Until completion, we are missing
00:02:09
one electron by taking it will receive a
00:02:12
minus charge. For example, if sodium
00:02:15
gives it its Electron. Further, for
00:02:17
example, if it is sulfur, sulfur is in the
00:02:20
6th group of the main subgroup and,
00:02:22
accordingly,
00:02:24
two electrons are missing before completion, having accepted them, it
00:02:27
will receive a charge of 2 minus, for example, sulfur
00:02:29
can receive these two electrons from
00:02:32
magnesium or from two sodium atoms further
00:02:36
if we take phosphorus, then phosphorus
00:02:38
is in the fifth group Until completion,
00:02:40
three are missing its charge and it will be 3
00:02:44
minus And it with a negative charge is
00:02:47
called anions.
00:02:49
So, an ionic bond is a bond between
00:02:52
ions of positive and negative
00:02:55
charge or if we let's talk about the
00:02:58
difference in electronegativity, then they
00:03:01
say an ionic bond is formed between
00:03:03
elements with the greatest difference in
00:03:06
electronegativity, if in numerical
00:03:08
terms, then this difference should
00:03:11
exceed two units according to the
00:03:14
pudding electronegativity table. So,
00:03:17
now let's see how it is customary to
00:03:19
build an ionic bond. Let's take
00:03:22
chloride as examples sodium
00:03:25
sodium chloride This is a well-known substance,
00:03:27
table salt, in this compound there will be an
00:03:31
ionic bond. By the way, it’s not difficult to notice
00:03:34
that the ionic bond involves not just
00:03:36
ions, but metal ions.
00:03:46
metal therefore,
00:03:49
Looking at the formula, we can guess
00:03:51
what the bond will be, including ionic.
00:03:54
So we begin to build the formula for
00:03:57
sodium chloride just as we did in the covalent
00:04:00
bond of the Lewis formula, so sodium has
00:04:03
1 electron on the outer level,
00:04:05
we will show this with one point And
00:04:08
chlorine has a total of electrons 7 but Before
00:04:11
completion, one thing is missing, its
00:04:13
electron will be depicted with
00:04:15
crosses;
00:04:17
this uses the method of dots and crosses;
00:04:20
at the first stage, between sodium and chlorine, an
00:04:23
electron will transfer to a common
00:04:27
pair from sodium to chlorine; a
00:04:31
common pair will be formed, but it is beneficial for sodium to
00:04:35
give up its electron; it is beneficial to accept electrons to chlorine;
00:04:37
therefore, in the ionic connection, it is customary to
00:04:40
show such a border, a bracket
00:04:43
around a non-metal, its charge is set to
00:04:46
minus And for the sodium ion we put the charge plus,
00:04:50
we got the Lewis electronic formula,
00:04:53
now below we will show the graphic formula
00:04:56
then between sodium and chlorine we will show the
00:05:00
shift in electron density, chlorine
00:05:03
receives a charge minus And for sodium it is plus But it
00:05:06
should It’s fair to say that
00:05:09
in fact in sodium chloride there will be more than
00:05:12
one sodium and one chlorine and it will
00:05:15
combine like this. Around the sodium ions,
00:05:18
ionic chlorine accumulates
00:05:21
around the chlorine, the environment is sodium soap, and
00:05:24
therefore the graphic formula reflects the
00:05:26
conditional relationship between sodium ions and
00:05:28
chlorine ions, the formation of ionic
00:05:32
connections and through the formulas of the
00:05:34
Bohr diagram, so
00:05:37
sodium has a nuclear charge plus 11 It has three
00:05:44
energy levels
00:05:49
on the First level Two electrons paired
00:05:52
on the second level of
00:05:56
its electron 8 they are also paired And
00:06:01
on the last level there is one electron that is not
00:06:04
burned, we showed here the sodium atom,
00:06:09
so chlorine has
00:06:11
electrons is also located according to
00:06:15
energy levels, but its core plus
00:06:18
17
00:06:19
levels is also 3,
00:06:23
and following the same logic,
00:06:26
we depict it electronically with crosses like this Two
00:06:30
electrons paired on the First level
00:06:34
8 on the second and they are paired like this on the
00:06:40
last level 7
00:06:46
and here it will be An unpaired electron
00:06:49
we showed this is an atom chlorine, now sodium
00:06:54
transfers its Electron here
00:06:59
and as a result, an
00:07:03
ionic bond is formed
00:07:05
in sodium.
00:07:08
Two energy levels remain
00:07:13
and it takes the form of it and it is an
00:07:18
inert gas and charge plus. Well,
00:07:22
accordingly, next to it is
00:07:24
chlorine with its nucleus plus 17
00:07:29
levels, it has three on the First 2 on the second
00:07:35
8 That is, the first second level they do not
00:07:40
participate in this case, but on the third
00:07:44
level, in addition to the electrons that
00:07:47
have chlorine of their own,
00:07:50
an electron from sodium appears, its charge will be minus
00:07:55
the only thing I would like to say is that in
00:07:58
this case when we show
00:08:01
these are formulas, for example, through
00:08:04
Bohr diagrams, of course, it may seem to you that
00:08:07
such a design, the formation of an ionic
00:08:10
bond is quite difficult, takes a lot of
00:08:12
time, but nevertheless it
00:08:15
allows you to show how, from the point of view of
00:08:17
atoms, electrons shift from
00:08:21
one element to another, in
00:08:22
fact, how such an ionic bond is formed
00:08:25
but in in principle, you can show,
00:08:29
depending on how
00:08:30
your assignments require you, you
00:08:33
can show a slightly more simplified
00:08:35
formula and, accordingly, the
00:08:38
Lewis formula, the structural electronic formula,
00:08:40
or through Bohr diagrams, and so it also
00:08:43
shows, you know, international
00:08:45
exams very often ask you to show it
00:08:47
through Bohr diagrams Exactly
00:08:49
therefore, I considered it necessary to show you
00:08:52
all the possible ways of writing Such
00:08:56
a form, so let’s give another example,
00:09:00
let’s say if it is calcium o Why
00:09:04
can I say that there is an ionic bond
00:09:06
because calcium is a metal and Oxygen
00:09:09
is not a metal,
00:09:11
so we build the formula in the same way as
00:09:13
we built for sodium chlorine, so calcium has
00:09:16
2 electrons on the outer level,
00:09:19
let’s remember that when we learned to build
00:09:21
Lewis formulas for atoms, we said in
00:09:25
which group the element is located from groups 1 to 4, there are
00:09:28
so many unpaired ones, so
00:09:31
calcium will have two unpaired ones for
00:09:34
oxygen on the outer level According to the
00:09:37
group number has 6 electrons, but from the fifth to the
00:09:41
eighth group we determine the number of
00:09:43
unpaired electrons by the number of
00:09:46
missing ones up to 8. Until the end of the electrons,
00:09:49
it means that oxygen will have two electrons,
00:09:53
respectively
00:09:55
unpaired, then a common
00:09:59
electron pair is formed, but this pair will immediately
00:10:04
go to
00:10:05
oxygen for more use and then it is
00:10:09
formed
00:10:11
formally double bond Why I say
00:10:14
formally because in reality there are much more ions
00:10:17
in this
00:10:19
sodium oxide. Therefore, we
00:10:22
reflect only the relationship between these
00:10:24
ions, but they are also the graphic formula
00:10:27
between calcium and oxygen, conditionally the
00:10:30
double bond goes towards
00:10:33
oxygen 2 minus 2 + Of course we
00:10:37
could depict both the transition formula and the
00:10:40
formula of the diagram that we showed
00:10:43
Bohr Let's show it in this case,
00:10:47
so calcium has a charge of its nucleus plus 20
00:10:54
It has four levels
00:10:56
on the First 2 on the second there will be
00:11:01
8
00:11:04
on the third also 8 and it has four
00:11:09
levels
00:11:10
and on the last we will depict Two
00:11:15
unpaired electrons, this is calcium for
00:11:19
oxygen, its diagram is a little simpler its
00:11:23
number
00:11:25
Ordinal 8 means it has two
00:11:29
levels
00:11:31
on the first two unpaired on the second two
00:11:35
pairs of paired and, accordingly, two
00:11:40
unpaired electrons this is oxygen
00:11:43
calcium will transfer to
00:11:46
oxygen one Electron here and
00:11:51
one more Electron here and here is an electron
00:11:55
and here is an electron and as a
00:11:58
result calcium has
00:12:02
a nucleus plus 20 at the first level it has two
00:12:08
as it was and will remain at the second
00:12:13
8 and at the third level it also has 8 and
00:12:19
it is in a state of
00:12:21
inert
00:12:23
gas argon charge 2 + but next to it there
00:12:29
will be oxygen, its nucleus will be plus 8,
00:12:34
the nucleus does not change at the first level 2
00:12:38
electrons and at the second level 2
00:12:43
paired electrons two more paired and one common
00:12:48
pair here is the second but moved
00:12:51
towards oxygen this is ours and it is calcium
00:12:55
2 plus this we have oxygen 2 minus So you and
00:12:59
I got Today in the lesson,
00:13:02
first of all, it distinguishes What is an ionic
00:13:04
bond; we were reminded What are ions How do we
00:13:07
determine the charges of these ions?
00:13:20
Of course, if you are asked
00:13:22
to construct such formulas for other
00:13:25
examples, I hope that with our help
00:13:28
now this will not be some kind of
00:13:30
difficult problem for you, especially since the
00:13:33
forms are too complex for you and no one will
00:13:36
ask you to build When we teach you how to do this
00:13:38
in high school High school
00:13:40
certainly has its own nuances
00:13:43
that we will talk about, but only
00:13:45
in high school. But here are examples of this type.
00:13:48
I hope you will also
00:13:50
succeed for today, I’m all
00:13:53
goodbye guys
00:13:55
[music]
00:14:04
[music]

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