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00:00:00
Hello everyone, very good evening.00:00:04
Welcome to a new live broadcast00:00:07
today, Thursday, September 17,00:00:13
2020. Sorry, we have 7 o'clock at night00:00:17
in Colombia and we start a00:00:21
new broadcast, a new video. On that00:00:24
physics occasion corresponding to the00:00:27
topic. of electrical circuits00:00:31
Yes we are going to see this topic practically00:00:34
from scratch I am going to share with you what I00:00:38
know about this topic eh for a00:00:41
high school level eh just as I learned it00:00:45
almost 33 years ago Yes when I attended00:00:49
the fourth grade of high school here In00:00:52
Colombia, that is, in the00:00:55
ninth grade, at that time, I saw this00:00:57
topic. I took the opportunity to thank00:01:00
my teacher Eutimio Ruiz, who was the00:01:03
one who taught me this topic and really,00:01:08
after 33 years, I remember00:01:10
his explanation perfectly because00:01:12
now I am going to tell you about it. how he00:01:14
did it, well I think it was a very00:01:17
very useful, very didactic method to be able to00:01:20
understand this00:01:22
electrical circuits. So we are going to see a00:01:25
small theoretical base and then we are going00:01:28
to proceed with the solution of00:01:30
three exercises specifically we are going to00:01:33
see a series circuit then a00:01:35
parallel circuit and at the end a00:01:38
mixed circuit which is the one that combines00:01:40
let's say the two arrangements that is to say in00:01:43
series and in parallel Yes, this video is00:01:46
practically dedicated to all00:01:49
high school or00:01:51
high school students who You see this topic for the00:01:53
first time, this is not physics at the00:01:56
university level, I can tell you at once Yes,00:01:58
because there are some who suddenly have00:02:00
the expectation Well, that I am going to00:02:01
explain physics Well, at the00:02:04
university level and that is not the case, it is physics00:02:06
for the secondary level Remember00:02:08
that those are the topics that I know and00:02:10
therefore they are the ones that I am in charge00:02:13
of sharing with all of you so00:02:16
Welcome, I quickly greet the00:02:19
people in the chat Because this video00:02:20
can be a little long So I I'm going to00:02:22
do it very quickly. First of all, I'm going00:02:25
to ask you, please, for good behavior in00:02:27
the chat, yes, as always. I request00:02:31
decent comments, demonstrating your00:02:34
education, your culture. Remember that this00:02:37
space is for you. Yes, so that you00:02:39
can take advantage of it so that you can leave your00:02:41
questions there. or your comments but in00:02:44
good terms and please00:02:47
always demonstrate your education. Unfortunately,00:02:49
those who do not know how to behave will00:02:52
have a temporary sanction, like00:02:54
a kind of yellow card, which is00:02:56
300 seconds out and if they repeat or yes, then it is00:03:00
about of a comment00:03:02
totally out of context out of00:03:04
place then receive the red card Yes00:03:08
then please you know that eh I00:03:11
'm going to ask you that a lot eh Well good00:03:14
behavior in this space that is the00:03:16
chat please I want it to be a00:03:18
decent community a community healthy eh who knows how00:03:21
to behave in this space that00:03:24
is totally educational00:03:26
okay So okay quickly Sorry I'm going to00:03:29
say hello I00:03:30
had already been writing here eh00:03:33
in the chat I had been saying hello to00:03:35
some people who have already connected00:03:36
for a while I'll come back00:03:39
quickly Elvis Calderón had greeted here00:03:42
cristal Medina flowers doro00:03:46
chiroma above Carlos Salamanca00:03:49
Piero vilca durá above José00:03:52
Hernández above Luis Reyes Darwin00:03:56
Arias well everyone is welcome eh I'm00:03:59
really very pleased to see that00:04:01
you are here already connected eh taking advantage00:04:04
of this space yes The video is00:04:05
recorded once I finish the00:04:08
explanation or the live performance. So you already00:04:10
know that the video is hosted here from00:04:12
my channel Julio Profe in the00:04:14
physics video playlist, yes,00:04:17
well, there you have various topics at your disposal00:04:20
from Panama, here you goes to Moisés00:04:22
Castillo also from Mexico Alberto00:04:26
Menchaca from Honduras joh English eh00:04:31
Carlos Chaparro welcome Carlos Daniel00:04:34
Uriel briseno welcome eh says Kevin00:04:38
uciel Gómez Thank you very much teacher I just00:04:40
started to see I started to carry00:04:44
electronic systems Brian Brian Steven López00:04:47
from Colombia Thank you very much Brian00:04:50
Andrés porcel Well, thank you very much00:04:53
then. Well, let's start because,00:04:54
as I say, this class can be a00:04:57
bit extensive, as I say, because it00:04:59
has a theoretical base. Then we will go with00:05:01
three examples. And well, the idea is to be able to00:05:04
leave in this video, let's say everything that00:05:06
I repeat. I know about this00:05:08
electrical circuits, which is a topic that00:05:11
can regularly be seen in00:05:12
high school, so well, remember to00:05:15
also subscribe to the Channel and activate00:05:19
the00:05:22
notification bell so you don't miss00:05:25
any of the new news.00:05:27
videos of the new transmissions, which00:05:30
is what I have been doing00:05:32
lately. So let's start with00:05:34
the explanation of what00:05:36
electrical circuits are, let's see, let's00:05:37
start by seeing what an elementary circuit is, let's00:05:40
see in00:05:42
electrical circuits, basically, let's00:05:44
consider what next first let's00:05:46
see what an elementary circuit is00:05:49
elementary circuit is going to be the first thing we00:05:51
see then we're going to do a00:05:53
circuit exercise of a00:05:56
series electric circuit then we're going to00:05:59
see one in parallel and finally a00:06:03
mixed electric circuit exercise yes00:06:07
This is basically, let's say the content00:06:09
of this video, we start with what00:06:11
an elementary circuit is, then we see the00:06:14
three examples, one in series, one in00:06:16
parallel, and one mixed. So let's00:06:18
start with what an elementary circuit is00:06:20
and as I said, I'm going to00:06:22
use the explanation that I received00:06:25
33 years ago, imagine when I00:06:28
was a boy of 13 or 14 years old, at the00:06:33
Corder school I was studying00:06:36
my ninth grade, that is, the fourth00:06:40
year of high school. Yes, at00:06:44
that time, and then I received that00:06:47
explanation by my00:06:49
physics teacher named Eutimio Ruiz, well, who00:06:53
sent a very special greeting. If at some00:06:55
point you have the opportunity to watch this00:06:57
video, yes, I still really remember it00:06:59
with great appreciation because it was my00:07:02
physics teacher, in fact, I built the00:07:04
circuits. and on a board Yes with00:07:07
cables with light bulbs uh a board that00:07:10
had I remember that it had some little holes00:07:12
then with screws Eh Well00:07:14
we secured the cables that we00:07:16
ourselves were assembling or building00:07:19
that is to say we bought well cable I remember it00:07:21
was cable number 14 and with clamps00:07:24
cold cut because we made different little00:07:27
cables of different lengths00:07:29
to place them on this table00:07:31
with screws and we made what was the00:07:33
ceiling to place the light bulbs00:07:36
we made the switches in short it was00:07:38
a really very very interesting thing00:07:40
because it was seeing the explanation also00:07:42
good Uh, so on the board, that is, the00:07:45
theoretical part, doing the exercises, but it00:07:47
was also going to build the circuits,00:07:49
uh, physically, that is, being able to see them00:07:52
practically in operation. That is00:07:55
an elementary circuit, basically it has00:07:57
three components. Let's see, the elementary prodo circuit00:07:59
basically has three.00:08:01
things that are precisely what make it up00:08:04
that are first a generator Yes here00:08:07
is a generator that in this case here I00:08:10
represent it with the letter g that is to say it is00:08:12
the source that we can say that it00:08:15
is a battery for example it is the one that is00:08:17
the source that that supplies the energy00:08:19
or in this case the voltage Yes this is00:08:22
where the voltage is generated yes00:08:24
we represent it with the letter V or v whatever you00:08:27
want to call it yes it is the generator I repeat it00:08:29
can be a battery a cell or when00:08:32
we plug in a device yes a to a00:08:35
outlet, which in that case would be what is00:08:38
called alternating current. Yes, if it is00:08:40
a cell or a battery, it is what is00:08:42
called direct current. So00:08:44
basically we have a generator. We have00:08:46
a conductor, which in this case is00:08:49
what we see here. That is the conductor,00:08:52
imagine. the cables or a cable that00:08:55
comes out of here from the battery does00:08:57
this whole route yes And also over here and it00:09:00
also has something called the00:09:02
resistance that is represented in this00:09:05
way yes it is a little symbol sometimes also00:09:08
eh you can find it like this no in00:09:11
this way something Like this Or you00:09:14
can find it like this or also this00:09:16
way or sometimes Well there are on other00:09:18
occasions I have seen that they00:09:20
represent it as a like a rectangle00:09:22
no and in here they put the name of the00:09:24
resistance For example if It is a00:09:25
resistor, in short, there are different00:09:27
notations, but the one I saw at that00:09:30
time was this one, that is, like a kind of00:09:33
Rayito, there it was. Well, basically00:09:36
the symbol that identified the00:09:38
resistors, so I repeat, an00:09:41
elementary circuit has these three components,00:09:43
a generator is To say, a00:09:45
voltage source has a conductor in this case,00:09:48
because what is the cable is that it comes out00:09:51
here from the generator, it makes this entire00:09:52
journey, it is connected to a resistance00:09:55
if here we have the resistance r, which is00:09:58
this one here, this resistance is r in the00:10:01
generator well obviously00:10:03
the voltage is supplied and I repeat then voltage that00:10:06
is the generator the resistance and what00:10:08
is the conductor or the cable So what00:10:11
is happening look and this is how my teacher explained it to me00:10:13
at that time he said00:10:15
look imagine that here we have In other words,00:10:18
a circuit is a00:10:20
cyclist race, yes. That is the example that he00:10:22
used, a cyclist race where00:10:25
here we have what is the00:10:27
feeding zone, those who feed, yes,00:10:30
Well, let's say they acquire the energy00:10:32
necessary to go compete or do their00:10:35
race. then ready they leave the00:10:38
feeding zone and this is where it is00:10:40
represented in this way yes as a00:10:42
kind of little arrow which is what is00:10:44
called the intensity of the current Yes00:10:47
then the current is going to be the00:10:49
cyclists yes that is what travels to00:10:52
Through the conductors, in reality, what00:10:54
is traveling there is00:10:56
electrical charges, the00:10:58
electrical circuits, let's say that they correspond to00:11:00
the part of electrodynamics, so to00:11:03
speak, that is, in physics there is00:11:05
electrostatics, which is the study of00:11:07
charges at rest. Yes, when00:11:10
For example, Coulomb's Law works, yes,00:11:12
here there is also a video that I00:11:14
made on that topic, yes, what00:11:16
electric force is and all of this is00:11:18
electrostatic and we also have00:11:20
electrodynamics, which is when00:11:22
charges are studied in movement00:11:24
so here we have electric charges00:11:26
in motion that come from here from the00:11:28
Source comes So the group of00:11:30
cyclists, as I repeat here, they ate,00:11:33
yes they fed, here comes the small group00:11:35
of cyclists making the trip along00:11:37
the track, yes let's say that in that case the00:11:39
driver or The cable is like the track00:11:41
where they move and be careful when they00:11:43
get here what they find is an00:11:46
obstacle and in that obstacle they00:11:48
burn that energy that is, they spend it00:11:50
completely to overcome this obstacle and00:11:54
once they leave the obstacle, let's say they00:11:56
leave without energy, but then they go down00:11:59
the track again until they return to the00:12:01
source, which is where they00:12:03
feed again and repeat the00:12:06
circuit. Yes, it is basically considered that,00:12:09
well, for the example that I am00:12:10
using, which I repeat, my00:12:12
physics teacher used, let's say that in the00:12:15
journey, that is, what is the route00:12:17
along the track or in this case by the00:12:19
driver, let's say that there is no00:12:21
energy consumption, that is, there the00:12:24
cyclists go on a completely00:12:26
flat track, eh, let's say perfectly00:12:29
paved so that you can00:12:31
imagine it like that. where there really is no00:12:33
expense or any physical effort let's00:12:36
not say that the expense occurs00:12:38
here really imagine that this was00:12:40
Well yes like a road I don't know full of00:12:42
stones or difficult yes of difficult00:12:45
transit So this is where00:12:47
they finally burn that energy that00:12:50
the Source has supplied to you. So00:12:52
look. We have here basically three00:12:54
variables that are the ones that we begin to00:12:56
consider in electrical circuits,00:12:58
which are the voltage, which is what00:13:00
the Source supplies, the intensity of the00:13:03
current and here the resistance r, those00:13:06
three variables,00:13:08
voltage. Intensity and resistance are00:13:12
related through this formula, which00:13:14
is the very famous Ohm's law. What00:13:17
I have here is of vital importance and is00:13:21
known as Ohm's law. That's what it's called.00:13:26
Yes, then what Ohm's law does is00:13:29
relate those three variables. the00:13:31
voltage, the intensity and the resistance00:13:33
This is the formula Well, I00:13:35
learned it at that time as vir Yes bir00:13:38
there is the v la i la r So it's like00:13:41
the way to memorize that little formula yes00:13:45
so as to always keep in mind the law00:13:47
of om I'm going to explain to you then,00:13:50
let's say what each letter consists of and in00:13:52
what units it is handled, then B, the00:13:54
letter b or v, whatever you want. Call it the00:13:57
voltage,00:13:59
which in this case is handled in volts. It is00:14:06
known as00:14:07
potential difference if the voltage00:14:10
is the v can be found with that00:14:12
term as potential difference00:14:15
then there is the voltage the i00:14:18
indicates the intensity of the current yes00:14:23
intensity of the current or simply00:14:26
the current no but well let's say that The00:14:29
real name or the strict name is00:14:32
current intensity and its unit00:14:35
is the famous amperes. Yes, this is00:14:38
when amperes and00:14:41
amperes appear. It is nothing other than the00:14:44
ampere unit, which is the unit of00:14:46
current intensity. It is equivalent.00:14:48
What are coulombs per second, that is,00:14:51
an ampere, you will remember here,00:14:53
it is basically a coulomb per second, C00:14:57
coulomb, which is the unit of00:14:59
electric charge, and then seconds is the unit00:15:01
of time, or what the00:15:03
ampere is indicating. Also, as it is like a00:15:04
kind of rate of change, that is, it indicates00:15:07
how many coulombs pass through a point of00:15:08
a conductor in one second, yes,00:15:11
basically that is what00:15:13
an ampere means. So we already have the00:15:16
voltage, the intensity and r, this r that00:15:20
we have here is the Resistance is00:15:25
measured or quantified in a unit00:15:29
called omio. Yes, omio is the00:15:33
unit of resistance and each one00:15:35
has its symbol. Let's see the voltage.00:15:37
So the volts, which are the letter b00:15:39
or v, the intensity of the current that goes00:15:43
in amperes is the letter a and the00:15:46
resistance is measured in ohms the00:15:48
symbol for ohms is this which is the00:15:51
Greek letter Omega Yes this is the00:15:54
Greek letter Omega So that way00:15:56
we already have the three variables voltage00:15:59
intensity and resistance that form the00:16:01
law of Ohm Here is What each00:16:03
of these variables and their00:16:06
corresponding units mean now to00:16:09
easily learn The Law of Ohm there is00:16:12
a little triangle which is the one that00:16:13
you probably already saw there in the00:16:16
thumbnail of this video, we are going00:16:18
to delete that, I repeat, they are the elements of an00:16:20
elementary circuit a generator that00:16:22
we have here a conductor that good are00:16:25
the cables through which the electric charges travel00:16:27
and and the resistance yes the00:16:29
resistance that is where the00:16:31
electric charges burn the voltage that they have00:16:34
obtained from the source in this case well00:16:36
where the cyclists, cyclists, sorry,00:16:39
they burn all that energy. So we're going to00:16:41
delete this from here and we're going to place00:16:45
the famous little triangle here, which is what00:16:48
will help us remember the00:16:51
law of Oh yes to always keep00:16:54
that in mind. So let's do it. In this00:16:56
way, let's see here00:16:59
we are going to draw a little00:17:00
triangle so we are going to split it00:17:04
here in half this way and again here like this00:17:07
this way And then00:17:10
there we are going to place the letters what we00:17:12
have here about the law of Oh00:17:14
we place the voltage here at the top00:17:16
and at the bottom the letter00:17:19
i and here the letter r there are00:17:22
then the three variables yes or the00:17:25
three letters of the law of Oh here is00:17:27
volt is intensity times resistance if I00:17:30
want the voltage well I cover the00:17:32
letter b here and then I have intensity over00:17:34
resistance here we can see what00:17:37
Ohm's law tells us if I want00:17:39
the intensity of the current Well00:17:41
we cover the letter i here and we have00:17:43
voltage over resistance if we say there00:17:46
the other one would come out formula intensity would be00:17:48
equal to voltage over resistance, I repeat,00:17:52
covering the letter i here. And if we want the00:17:54
resistance, we simply cover00:17:57
the letter r here and what we observe is00:18:00
voltage over intensity.00:18:06
r00:18:10
this is the voltage intensity00:18:13
over resistance and this is the00:18:15
resistance which is voltage over00:18:17
current intensity all of this little00:18:20
triangle that is quite useful to00:18:22
remember this concept of Ohm's law00:18:25
so I repeat This is what denotes a00:18:28
elementary circuit and there is also another little00:18:32
formula that is important to know. Well, we00:18:35
already have the law of I'm going to00:18:36
remove it. Yes, because well, we already have it00:18:39
here summarized in the little triangle and there is00:18:42
another one that we are going to need and that we are going to00:18:44
use also here in the00:18:46
development. Of the examples, which is the00:18:48
formula for power, yes, the power00:18:52
that it is is practically, that is, the00:18:55
physical concept of power is00:18:58
related to the quotient00:19:01
between work and time, let's remember that00:19:03
power is the speed with which00:19:05
work is done. So in this case, in00:19:08
the case of electrical circuits,00:19:10
power is defined as voltage times00:19:13
intensity. This is another very00:19:15
important formula that we must keep in mind, yes,00:19:19
voltage times intensity gives us what00:19:22
power is and we are going to00:19:25
add that here in the list of variables00:19:28
Sorry Ah well I deleted the resistance it doesn't00:19:31
matter let's add it here we already00:19:33
have the previous ones yes let's remove this00:19:34
to gain space In the end00:19:37
I'm going to have to delete all this because00:19:38
the examples come so voltage00:19:40
we already know that it is in volts The00:19:42
intensity is in amperes, the intensity of00:19:44
the current and p, which is the power, as I00:19:47
told you, is expressed in watts. Yes,00:19:52
watts is the unit for power that00:19:56
is denoted by the letter W, which00:19:59
is surely what you have seen in the00:20:01
light bulbs in the devices. Electrical, let's00:20:04
always say on the back, not00:20:06
of a television, of a fan, of an00:20:08
air conditioner, Well, a lamp,00:20:11
any device that you, uh,00:20:14
household appliance, for example, has. Let00:20:16
's say like a label, like a00:20:17
kind of sheet, uh, where is00:20:20
the information, the specifications? of00:20:23
that device and it always has the information on00:20:25
how many watts it consumes, well, that's what00:20:27
in the end they charge us. No, yes, when00:20:30
we receive the electricity bill,00:20:33
there comes the consumption that00:20:35
generally, well, the unit00:20:37
used is the kilow hour, yes. In other words, kilow00:20:40
is a kilow is 1000 W and obviously,00:20:42
that is multiplied by time.00:20:44
Well, each device is in00:20:46
operation, but for that matter, well, of00:20:48
any electrical circuit that one00:20:49
analyzes, be it the elementary one or any00:20:52
of these that we are going to see now. Well,00:20:54
we have that the power is measured in00:20:56
watts, that is, basically here and it is being00:20:59
used in this device. Imagine00:21:01
that this is an electrical device00:21:02
connected to the circuit. Well,00:21:04
let's say it is investing or it is00:21:07
also spending a power. Yes, in the end,00:21:10
let's remember that as I told them. It is the00:21:12
speed with which work is done,00:21:14
it is work over time, therefore00:21:16
let us remember that watts00:21:19
refers to seeing a watt, it is what is00:21:21
called a joule or a joule, yes, remember00:21:24
me, one joule per second. There is that. This00:21:27
is what a watt means, a00:21:29
jou per second or a Joule per second,00:21:31
it is also like a rate of change00:21:34
in the end. I repeat, it is indicating the00:21:36
speed with which work is done,00:21:39
so also for00:21:41
power we are going to use another triangle.00:21:44
We have the one about Ohm's law, this one00:21:46
here that summarizes the three variables,00:21:48
voltage, intensity and resistance for00:21:51
power. We are going to use another little00:21:52
triangle that I am going to draw here.00:21:55
Let's see if it fits, if this one is going to00:21:57
do it a little more. smaller so00:21:58
that it fits where we are also going to00:22:01
collect those three variables we are going to00:22:03
do it like this we divide here we draw00:22:07
this dividing line and we are going to place00:22:10
these three letters so here00:22:12
we have power here we have voltage00:22:15
and here we have intensity yes there it00:22:18
is Look at the power if I want the00:22:20
power I cover the letter p And what do I have left00:22:23
voltage by intensity there we have it00:22:25
if I want the voltage if I want the00:22:28
voltage then we simply cover here00:22:30
we cover the letter b and what do we have left00:22:33
power over intensity p over I There00:22:36
it is and if we want the intensity of the00:22:39
current then we cover this00:22:42
letter we cover the letter i here And what do00:22:45
we have left over power over voltage Yes00:22:47
then the little triangle comes out well those00:22:51
formulas I repeat what link those three00:22:54
variables power voltage and intensity00:22:56
of the current let's say that this is the00:22:58
primitive formula So to speak for00:23:01
the power because here I could even00:23:03
insert the voltage taking it out of00:23:05
Ohm's law if I insert the voltage here00:23:07
as i * r then I will have i * r00:23:10
* i that is, in the end it will produce I00:23:13
cu for r, that is, they could come out as other00:23:16
additional formulas for the power.00:23:18
Well, if we make use of, let's say, the00:23:20
information that I have here in the law of,00:23:22
but no, we are not going to fill ourselves with more00:23:23
formulas, we are going to work only with00:23:25
these two little triangles, I repeat the one that00:23:28
we gives the summary of Ohm's law and00:23:30
this is what summarizes the00:23:33
power formula. So this is what00:23:36
refers to an00:23:38
elementary circuit, I repeat, the one that has a00:23:41
generator, a conductor and a resistor00:23:44
and then understand that that runs through00:23:47
the circuit Well, if it is the intensity of00:23:50
the current, it is a set of00:23:52
electrical charges that in the end can be00:23:54
associated with cyclists who00:23:56
make a route at a glance and who00:23:58
burn their voltage or the energy obtained00:24:01
in an obstacle that they have to overcome00:24:03
What is the resistance in that case? Okay,00:24:06
so with this. Now we are going to00:24:09
move on to the first example that has to do00:24:12
with what a series circuit is. We have00:24:16
already seen the elementary circuit. Yes,00:24:18
let's say that this is already out. Let's now move on00:24:21
to the series circuit. Yes, we are going to00:24:23
place the title here when it says00:24:26
that it is a series circuit, it00:24:28
refers to the way in which00:24:30
the resistors are connected. So00:24:33
we are going to see it in the following00:24:35
way, we are going to place the00:24:37
generator here again, a generator that00:24:40
we represent like this with the letter g and00:24:42
then we are going to make the00:24:45
circuit with three resistors. Sorry, I'll00:24:48
check my notes here. Uh-huh, there are00:24:50
three resistors, so well, here00:24:52
we have one. We're going to draw another one here.00:24:56
This way, we come like this and here00:25:01
we're going to draw the other resistor.00:25:05
It would be like this, there are then00:25:07
three resistors, we are going to place the00:25:10
values that are eight, here we have00:25:12
a resistance of 8 ohms, then00:25:15
we have one down here of 2 ohms. If00:25:19
we remember that it is the Greek letter omega,00:25:21
and also over here we have 5 ohms, we are going to00:25:25
enter the value if here I can00:25:27
get 5 ohms and the Source Then00:25:31
we have that it is supplying 30 V yes00:25:35
That is the voltage or the00:25:37
potential difference Well, it is providing00:25:39
the Source This is what is called a00:25:41
series circuit For what is called00:25:43
series Because if we think about the00:25:45
cyclists when they leave the Fountain they are00:25:48
going to encounter a first obstacle here,00:25:50
here the same group of cyclists00:25:53
encounters another obstacle and here the00:25:55
same group of cyclists encounters00:25:57
a third obstacle and then they return00:26:00
here to the Source to00:26:02
feed again And in this way repeat00:26:05
what the race or circuit is. Yes,00:26:07
that is why you have also heard the00:26:08
term circuit in00:26:10
cycling races, so there it is, look, there are00:26:13
three resistors placed in series or00:26:15
in a manner. consecutively along the00:26:18
conductor, if the conductor leaves here, he00:26:20
makes this entire journey until he returns00:26:22
to the source and in that journey, well,00:26:24
we have the three resistances there. Well,00:26:27
someone will wonder what happens if there is no00:26:29
conductor, sorry if there are no resistors.00:26:32
So, we would have This is like this, yes, that is00:26:36
to say, I have the Source, I have the, the00:26:38
generator comes, which is the conductor, and00:26:41
again returns to the Source. Yes, there is no00:26:43
resistance. Well, this is when the00:26:45
famous eh short circuit occurs. No,00:26:48
yes, be careful with this, be careful with the short.00:26:51
circuit see here I draw the00:26:54
danger sign be careful with that because batteries eye00:26:59
behold with that you see This is what is called00:27:02
the short circuit beware because What happens00:27:05
there the electric charges well00:27:08
they receive a voltage the electric charges come out00:27:10
Yes but it turns out that They have nowhere to00:27:13
burn that voltage so00:27:16
they return to the Source with all that00:27:18
energy Yes, like with all that eh that00:27:21
momentum and that is when the short occurs00:27:24
the short circuit yes surely00:27:26
when you have seen that one00:27:29
clearly connects a plug to an outlet And00:27:32
suddenly the two little wires are00:27:34
stripped like this and for some reason they make00:27:36
contact because we already know what is00:27:38
happening, we cannot even leave the house00:27:40
without electricity because I repeat in00:27:43
that case because00:27:45
the two wires have been found and in their path There is no00:27:47
resistance in agreement. In other words,00:27:50
there is no place to burn that voltage. For that00:27:52
reason, it is when the short00:27:54
circuit occurs, so that you keep that00:27:56
in mind, that is not why it is one of the00:27:58
fundamental elements of the00:28:01
electrical circuit because it is the resistance or in00:28:03
that Good case we have three resistors,00:28:06
yes that is precisely where. Well, the00:28:09
electric charges or the current are going to00:28:11
use up that energy that they have received from00:28:14
here from the generator. So we are going to00:28:16
solve this circuit, I repeat, it has three00:28:19
resistors connected in series and be00:28:21
careful with the key to resistances00:28:23
in series it turns out that here what we are going00:28:26
to do is move on to what is an00:28:28
elementary circuit that we always see to solve a00:28:31
circuit. The idea is to take it to an00:28:33
elementary circuit, that is, like the one I00:28:35
just showed you that only has00:28:38
one resistance So look what00:28:40
I'm going to do, basically I'll make00:28:42
the same drawing again, well the generator.00:28:45
Here is my generator or the Source, yes. And00:28:48
this comes like this.00:28:49
And then what I do is draw00:28:52
with a single resistor. Let's see in this00:28:56
case those three resistors. that I have00:28:58
there connected in series now one thing00:29:01
Before I forget, I have00:29:03
told you that the charges do not come out like that, but they00:29:05
could perfectly come out in the other00:29:07
direction. Nothing happens, it is exactly the00:29:09
same or I am doing it, let's say00:29:11
here in the sense of the hands of the00:29:14
clock yes clockwise but if00:29:16
they do it in the other direction Nothing happens00:29:17
Remember that Well in the end there for00:29:19
the current it is indifferent Well the00:29:21
direction it takes Well Unless00:29:23
here it is a battery eh yes00:29:26
whatever is direct current or00:29:28
direct current, but when it is00:29:30
alternating current, it is what we00:29:32
receive from an outlet00:29:35
because alternating current is precisely what it00:29:37
is saying is that the electrons00:29:39
or electrical charges go from one00:29:41
direction to another or So there really00:29:43
is no problem there. Well, in which direction let's00:29:45
move, then what I want to tell you00:29:47
is that we have the circuit with the three00:29:49
resistors connected in series and we are going to00:29:51
take it is an elementary circuit, eye, a00:29:54
generator, a conductor, a single00:29:56
resistor00:29:57
and Here we go. to have what is called the00:29:59
total resistance, okay, and then00:30:02
this is where the key fact comes in or the00:30:04
key to what series circuits are.00:30:06
In series circuits, the00:30:08
total resistance is going to be put here00:30:12
because it is to00:30:14
calmly add the Let's say resistors00:30:17
are connected to the circuit00:30:20
in this case because I have three00:30:22
resistors one resistor two00:30:24
resistors TR the current sum is made00:30:27
of those three quantities that00:30:29
have to be in omios00:30:31
yes Let's say if there were more resistors00:30:34
connected in series well00:30:36
I simply continue No until resistance n Yes, if there are00:30:40
more resistances there then I add00:30:42
all those resistances00:30:45
to obtain the total resistance because00:30:48
in this case let's do the sum and see00:30:49
we have 8 + 2 are 10 + 5 are 15 ohos in00:30:55
that case then The total resistance is going to00:30:58
be 15 ohms. There it is, I simply00:31:01
add the three quantities, the three00:31:03
resistances. And in that way, I already have the00:31:06
total resistance for what is the00:31:09
elementary circuit that corresponds to00:31:11
this series circuit. If I repeat where00:31:14
the resistances are in this case. three00:31:16
resistors are connected00:31:18
consecutively or in series, so00:31:22
please keep this in mind, it is the00:31:24
key to series circuits, the00:31:26
total resist is the sum or the sum00:31:30
of the partial resistances or those00:31:33
that are connected along that00:31:36
series circuit Well, it turns out that now00:31:38
we are going to solve the elementary circuit00:31:41
Here is 30 V supplied by the Source, that00:31:44
is, it is the voltage or the00:31:47
potential difference that the electric charges come out00:31:49
So we have to find out how much00:31:51
the intensity of the current is and it is00:31:54
here When we are going to use this, what00:31:57
is Ohm's law? Yes, I need the00:31:59
intensity. I know the voltage. I know the00:32:02
resistance. That is, I know these two00:32:04
variables. I am missing the intensity.00:32:11
I And what do we have00:32:14
left, voltage over resistance B over00:32:17
r There it is And then we are going to00:32:20
replace How much is the voltage is 3000:32:22
vol Here is 30 V in the numerator in the00:32:26
denominator we have the resistance which00:32:28
is 15 ohms 15 ohms and then we00:32:32
do the division 30 divided by 1500:32:35
that gives us 2 and we have voltage eh Sorry00:32:38
volts over ohms Well it gives us the00:32:41
unit that we saw previously for the00:32:42
intensity of the current which is the00:32:45
amperes What does that mean So00:32:47
we have a charge eh Sorry a00:32:49
current intensity of 2 amperes00:32:52
that is 2 coulombs per second yes it00:32:55
is giving us an idea of how many00:32:57
electric charges are transiting or00:33:00
traveling through the circuit because each00:33:02
second in this case it would be two00:33:04
coulombs per second so there00:33:06
we already have what the intensity of the00:33:09
current is. So now look at the00:33:11
following, we are going to take advantage of the fact that we are00:33:13
here to find the power, what00:33:17
we would call the total power of this00:33:20
circuit. Well, in this case, this00:33:22
elementary only has one00:33:23
resistance. So to calculate the00:33:25
power, we use this here.00:33:27
It would be multiplying voltage by intensity.00:33:30
I cover the letter p Let's see, let's00:33:32
remember it here if I cover the letter00:33:35
p we cover this p here what do we have left is00:33:38
voltage by intensity to find the00:33:41
power in this case of the00:33:43
elementary circuit then we replace the00:33:46
values the voltage is 30 30 V There is00:33:51
and this multiplied by the intensity00:33:53
which is 2 amps we multiply 30 * 200:33:58
gives us 60 and we have 60 W That is where00:34:02
the unit watts appears which is00:34:04
represented with the letter W yes remember00:34:07
that it is watts or watts it can also be00:34:09
pronounced as watts and00:34:12
This means that here we have a00:34:14
total power of 60 W. Yes, in the case00:34:18
of this elementary circuit, when we00:34:20
have already solved the elementary circuit,00:34:23
what we do is Now we00:34:25
go back to the original circuit, let00:34:27
's say the one from the previous stage to start00:34:29
solving. what happens in each00:34:32
of the resistors So let's00:34:35
delete this from here and then let's00:34:37
see Well, what from here What thing from here I00:34:40
can transfer to that drawing Well, it00:34:42
turns out that, as the group of00:34:45
cyclists leaving the fountain told you, In this00:34:47
case we already know that there are 2 amps. I00:34:49
could draw it here, for example in the00:34:51
original circuit, here we have a00:34:54
current intensity of 2 amps.00:34:58
Yes, imagine that it is a group of00:35:00
two cyclists. Yes, yes, so that00:35:01
we can understand it, two come. cyclists00:35:03
here those two cyclists have to go00:35:05
through this one through this obstacle go through00:35:08
this one through this other obstacle then through00:35:11
this one to return again to the Source00:35:14
feed themselves and repeat the00:35:16
circuit again Then at the end or00:35:20
necessarily the two eh cyclists00:35:23
pass through these three resistors So00:35:25
the intensity Here is also going to be00:35:28
2 amps in this one It's going to be 2 amps and00:35:31
here also 2 amps so if00:35:34
we number those resistances if that were00:35:37
resistance one resistance two00:35:39
resistance three Well here we would have the00:35:41
intensity one intensity two intensity00:35:44
three that can also be done, that is,00:35:45
done as a numbering of the00:35:47
resistances so that in each one of00:35:49
them we are supplying or00:35:52
detecting what the data is, that is, the00:35:54
resistance data in that case of00:35:56
current intensity now. We are going to00:35:58
give the voltage and we are going to give the power00:36:00
Yes in each of them for the end00:36:02
confirm that it gives us what we have here that00:36:05
is to say the elementary circuit00:36:08
okay So we already have for each00:36:10
resistance good for Yes for each00:36:12
obstacle the value of its resistance in00:36:15
omios and the value of its00:36:17
current intensity in amperes we would be00:36:19
missing we already have this we already have this00:36:21
we are missing the voltage and we are missing the00:36:23
power if I want Find the voltage in00:36:25
each of these places, let's say in each00:36:28
in each00:36:29
obstacle because I come here to the little triangle00:36:31
of Ohm's law we cover the letter b and00:36:34
what we have left is intensity times resistance00:36:36
So I must multiply these00:36:39
two values here is the intensity and00:36:41
here is the resistance so I00:36:43
multiply 2 * 8 what gives us then 16 what00:36:47
16 V because I am finding the voltage not00:36:50
voltage is intensity times resistance00:36:52
I multiply these two quantities gives me 1600:36:54
V I multiply here two * 2 gives us 4 V00:36:59
I multiply here 5 * 2 gives us 10 v and in the00:37:04
end I can verify that the sum of00:37:07
the three voltages well it gives me the00:37:09
total voltage let's see here 16 + 4 gives us 20 and 2000:37:15
+ 10 gives us 30 30 vol of course the group of00:37:19
cyclists the two cyclists who leave00:37:21
here from the Source well fed come00:37:24
here to this first obstacle and and burn00:37:27
16 vol yes they burn 16 vol they save 14 vol00:37:31
they continue their journey here they reach00:37:33
another resistance and burn 4 vol they had00:37:36
14 they did not burn 4 V How much do they have left they have00:37:39
10 V left which is what they use here in00:37:42
the third obstacle here they spend the00:37:44
other 10 V Yes and the rest of the energy00:37:47
that they had left and when they leave here00:37:49
from this point, they leave00:37:51
practically exhausted without energy, so they00:37:54
return to the Source, they feed, see00:37:57
it here, erasing the g and they feed and it comes00:38:00
back And the circuit is repeated, I repeat the00:38:02
example. of the cyclists here who00:38:04
feed on the fact that these are obstacles00:38:07
Well, it is actually quite useful, quite00:38:10
easy to understand to know well that00:38:12
in each obstacle an amount00:38:15
of energy is burned, now look at the following, the00:38:17
more difficult the obstacle is, the00:38:19
greater the amount of energy burned00:38:22
and look what is happening here We have00:38:24
here an obstacle or a resistor of 800:38:27
ohms, this one has more resistance than00:38:29
these ones here. How much was burned here? 16 V was00:38:32
burned more voltage than here and here, that is to00:38:35
say, there is a directly00:38:37
proportional relationship. Of course, here we have it. Not00:38:40
here. Look at the voltage, that is, I get it00:38:43
from here, not from Ohm's law. The voltage and00:38:45
resistance are quantities00:38:47
directly proportional to the greater the00:38:50
resistance, that is, the more difficult00:38:52
the obstacle is, the more voltage will be00:38:55
burned. I agree and that is what is00:38:57
happening right here. So it is another00:38:59
way to verify that this is00:39:02
well resolved. One way, as I tell you, is00:39:05
to add the three voltages and we see then that00:39:07
the total voltage corresponds to that of the00:39:09
elementary circuit. Also, then00:39:11
here we could practically ensure00:39:14
that In this case, for the00:39:16
series circuit, the total voltage, that is, the one00:39:18
supplied by the Source, will be the00:39:21
sum of its partial voltages, so to00:39:24
speak, in this case, it is B1 + b200:39:27
plus B3 and also in terms of the00:39:30
intensity of the current we could00:39:32
assure that the total intensity yes the00:39:36
Total current that runs through the circuit00:39:38
because it will be the same in all00:39:41
places it will be the same intensity one00:39:44
intensity two intensity three etcetera00:39:47
if there were more intensities Sorry more00:39:48
resistors connected because the00:39:50
intensity is the Because as I00:39:52
told them, the group of cyclists00:39:54
must go through all00:39:57
the obstacles, they really have no other00:39:59
option, so these are little things that00:40:01
must be kept in mind for the00:40:03
series circuits. We already see the first00:40:04
formula, that of Total resistance, which00:40:07
is the sum of the partial resistances,00:40:09
that would be another one, yes, the total voltage,00:40:12
the voltage supplied by the Source, since it00:40:14
is the sum of the partial voltages and00:40:17
the intensity of the current, this00:40:19
intensity here is the one that comes out of the00:40:20
Source, since it is the same in all00:40:23
places. Yes so that we keep this in00:40:25
mind in series circuits Now00:40:29
we are left lacking the power yes the00:40:31
power in each place Here is00:40:33
power What is voltage times intensity00:40:36
So what do we do in that case to00:40:39
increase the power Well in each place or in00:40:42
each site We are going to place the power00:40:43
of this one here and we are going to put this one00:40:46
here to allocate the power. I00:40:49
multiply the voltage by the intensity.00:40:51
Here I have the voltage and I have the00:40:53
current, that is, the intensity of the00:40:54
current, which is in amperes,00:40:56
I multiply 16 * 2 which are 32 W if00:41:00
we remember the unit of power which00:41:01
is w here I multiply then00:41:04
voltage by intensity I multiply 4 * 200:41:07
that gives me 8 W and here I multiply00:41:11
voltage by intensity I multiply 10 * 200:41:14
which gives us 20 W in the end of course I can00:41:17
verify that the sum of the powers00:41:20
gives me the Total power that had been00:41:23
determined here in the00:41:26
elementary circuit, let's see we have00:41:28
32 W + 8 W here we have 40 W and 40 +00:41:34
20 There are the 60 W which I repeat is the00:41:37
that we had determined for the00:41:39
elementary circuit. Then00:41:41
the powers are also added, let's say the00:41:43
total power in this case because it is the00:41:47
sum of the powers: power 1 plus00:41:50
power 2 plus power 3 and well, if00:41:53
there were more devices or more00:41:56
artifacts connected there, more00:41:57
resistances would be add the powers00:42:00
that have been determined in each of00:42:02
them well then we have solved00:42:05
the series circuit I repeat from the00:42:07
original circuit we move on to an elementary circuit00:42:09
we solve it and then I return here00:42:12
to be able to determine in each place or00:42:15
in each resistance all its00:42:17
characteristics resistance intensity00:42:20
voltage and power there they are look at the00:42:22
four uh the four parameters or the00:42:24
four uh characteristics in each of00:42:27
these places for that series circuit we00:42:31
already finished it00:42:33
So now this one is solved first00:42:36
let's now solve a parallel circuit00:42:39
Yes let's go Let's see how00:42:42
the circuit works in parallel. Let's delete00:42:44
here. Let's also remove this from00:42:47
here and then next we'll00:42:51
draw the circuit in parallel. Yes with00:42:55
resistors00:42:56
connected in parallel. Parallel Here it00:43:00
is.00:43:02
we have the generator let's00:43:05
draw it here the g the00:43:08
voltage source comes the conductor this00:43:11
way it does let's say this route00:43:14
here we also go down00:43:17
Here we come here and then it is00:43:21
here when let's say a00:43:23
kind of bifurcation occurs let's say here00:43:26
conductor takes Two paths, one here00:43:29
yes to let's say find a00:43:32
connected resistor here and the other one here00:43:36
where we have another connected resistor00:43:39
and in that way we finish the00:43:42
circuit. So that let's say is the00:43:45
model or the classic form of what00:43:48
a parallel circuit is, I'm going to place00:43:51
the values00:43:52
So we have here a source that00:43:56
supplies 12 V yes what is the00:43:59
generator we have a resistor here00:44:01
of 3 ohms this one has 3 ohms and this is00:44:05
going to be 6 ohms Yes here it is00:44:08
then the two resistors in00:44:10
parallel So what of always or what00:44:13
I was telling you now we are going to take this00:44:16
to an elementary circuit Yes we are going to00:44:19
take it to a circuit with a single00:44:22
resistor to be able to do its analysis00:44:25
and And in that way then we can00:44:28
return to analyze the00:44:31
original circuit Here it is then this would be00:44:34
The elementary circuit, I repeat, I have00:44:36
a parallel circuit here, that is, I have00:44:38
only two resistors connected,00:44:40
as the name says. Don't remember in00:44:42
mathematics the ones in geometry.00:44:45
Sorry, two lines that are parallel, not like that,00:44:47
for example, two segments that never00:44:48
touch. Well, here we see This also in00:44:50
the way in which the two resistors are arranged,00:44:53
they are like00:44:56
parallel conductors that in the end Well, of course what00:44:58
they do is good, they meet00:45:00
here, that is, this conductor and that one00:45:02
meet at this point, the same thing, this one00:45:04
here and this one. from here they are found at00:45:06
this point that in the end Well, they lead to00:45:09
what is the source Not to the00:45:11
voltage source So that is what00:45:13
identifies a parallel circuit, they are no longer00:45:18
consecutively connected resistances as we saw00:45:20
before, that is, as the circuits00:45:22
in series but now they are00:45:24
connected or arranged in parallel00:45:27
Sorry for a00:45:28
moment I'm going to drink water00:45:33
because let's see my throat is getting dry00:45:35
to talk so much we're missing we're00:45:38
missing that part we're not going here in00:45:40
Parallel then we're going to work on a00:45:41
mixed one To close the entire explanation,00:45:44
we continue then as I said, we are going to00:45:47
move on here to an elementary circuit that00:45:50
has 12 V here. Yes, that is, this does not00:45:52
change, it is what the source provides and00:45:55
be careful here. Here we have a00:45:57
total resistance. Let's see how it is calculated. that00:46:00
total resistance pay attention here Here00:46:03
mathematics comes in again it turns out00:46:05
that in parallel circuits00:46:07
the following formula is applied we are going to00:46:09
write it here one over the00:46:12
total resistance is equal to 1 over00:46:17
resistance 1 + 1 over resistance 200:46:22
and well This more ellipses00:46:25
here I'm going to remove that for a moment so00:46:29
on more if there were more00:46:31
resistors connected in parallel well00:46:33
until we reach resistance n look what00:46:35
is happening happening there it is already a00:46:38
sum but of the00:46:40
multiplicative inverses or what they are called00:46:42
the reciprocals Yes, I no longer work with the00:46:45
normal resistances as we saw00:46:47
now in the series circuit but00:46:49
now they are inverted Yes now that is what00:46:51
characterizes what the00:46:53
resistors connected in parallel are, if00:46:55
I want the total resistance I have to00:46:58
start with the inverse of the00:47:00
Total resistance which will be the sum of00:47:03
the inverses of each of its00:47:06
partial resistances, attention that00:47:08
when I say inverses I mean what00:47:10
are multiplicative inverses that is, what00:47:12
the reciprocals are now at the end if00:47:15
I want to obtain the resistance total00:47:17
well after I do all this then I00:47:19
have to invert this here so00:47:22
what I do in the end is place that is to say00:47:24
that r t is going to be equal to 1 it is going to be 100:47:29
over all this here that is 1 over00:47:32
R1 + 1 over00:47:35
r2 And so on until I00:47:39
reach 1 over rn Yes, that is, in the end what00:47:43
I do there is practically clear,00:47:46
uh, invert the result of this entire00:47:48
operation, here I give it like this turn00:47:51
to be able to find the00:47:54
total resistance ultimately what is What happens here00:47:57
is practically like raising all that00:48:00
sum to the exponent -1, let's remember what00:48:03
happens in the potentiation, not that00:48:05
is, here inside the parenthesis I00:48:07
would have 1 over R1 + 1 over r2 And so00:48:13
on until I reach 1 over rn00:48:15
But in the end All that I do is00:48:17
raise it to the exponent -1 to be able to00:48:20
do this to be able to do the00:48:22
multiplicative inverse And that way I can00:48:24
find what the total resistance00:48:27
is that we have here. So let's00:48:30
do that calculation for those two00:48:32
resistors that we have connected In00:48:35
parallel let's say that for our case00:48:37
the formula would only be up to there00:48:39
it would be 1 over RT ig 1 over R1 + 1 over00:48:43
r2 So let's see how it is done let's00:48:46
see it then for this situation00:48:49
we would have So as I told you if I00:48:51
want to find RT what I do This is the00:48:54
total resistance that I have here,00:48:56
I take the inverse of resistance 100:48:58
Let's assume that this is R1 So it00:49:00
would be 1 terci plus the inverse of r2 this00:49:05
would be r2 So it would be + 1/6 yes the00:49:09
inverse of this plus the inverse of this I00:49:11
add them and in the end I have00:49:15
to raise them to -1 yes as I told you or00:49:18
in the end it is like good to do that sum of00:49:19
those two fractions and then do one00:49:21
on that to be able to find the00:49:24
total resistance Now this is arithmetic00:49:27
see let's remember that here I can00:49:29
change the fraction for example a00:49:31
third to make it easier I00:49:34
cannot change it for the fraction 26 this00:49:38
fraction 1 third I change it by 2/600:49:40
I multiply by two above and by 2s below00:49:42
so that we have00:49:44
homogeneous fractions 2 /6 + 1/6 all this to the -100:49:48
at the end here because the sum of these two00:49:50
fractions is going to give me 3/6 36 to the -100:49:55
3/6 Well when a fraction is raised00:49:57
to the exponent -1 what happens It is00:49:59
inverted, it is not flipped and we would be left00:50:02
with 6/3, well all this raised to the 1st. That is00:50:05
simply 6/3 but 6/3 or 600:50:08
di 3 gives us in the end 2 What does it mean00:50:11
that the total resistance is 2 ohos There it00:50:15
is, look, then in a few words,00:50:17
two00:50:18
resistors, one of 3 ohms and the other of 600:50:22
ohms, connected in parallel will00:50:24
produce a total resistance of 200:50:27
ohms. Here it is, look. That is the00:50:29
procedure that must be done by adding00:50:31
the reciprocals or the00:50:34
multiplicative inverses. of those resistors00:50:36
connected in parallel and at the end00:50:38
invert all that result that is, do not00:50:41
forget this Raise to -1 Yes so that00:50:44
in the end it gives you the00:50:46
corresponding result the correct result of00:50:48
the total resistance so00:50:51
this is very important for the resistors00:50:53
connected in parallel parallel So now00:50:57
we are going to delete this from here and we are going to00:51:00
solve the elementary circuit so that00:51:02
once solved we return here to the00:51:05
circuit initially proposed and be able to00:51:08
find in each place, that is, in each00:51:10
resistance, the missing elements, that00:51:13
is, to be able to find their intensity of00:51:15
the current the voltage that has been00:51:17
burned in each of them and also00:51:19
the power so let's see I already have00:51:21
voltage here in the elementary circuit and00:51:24
I have resistance I have these two things00:51:26
here look at voltage and resistance00:51:28
I can calculate the intensity using00:51:30
Ohm's law then let's remember that00:51:33
intensity There is intensity is00:51:36
voltage over resistance remember00:51:39
we cover the letter i here what do I have left B00:51:41
over r so B over r voltage over00:51:45
resistance let's replace the data00:51:47
the voltage is 12 vol There it is and what00:51:52
is the resistance that is two omios00:51:56
we do the division 12 / 2 it gives us 6 and let00:52:00
's remember that this division of units00:52:02
that is, we look here that we are00:52:04
finding not that they are uh the intensity of00:52:06
the current that is expressed in00:52:08
amperes What does this mean so00:52:11
that a small group comes out let's imagine that there are00:52:14
six cyclists 6 amperes yes 6 coulombs00:52:18
per second is what is coming out of00:52:20
here from the Source to make the route00:52:22
of that elementary circuit so let's00:52:25
imagine that they are the six cyclists00:52:27
So we are going to delete this from here and00:52:30
here we can now say well that in this00:52:32
resistance because we have a00:52:34
current intensity of 6 amps, what we are00:52:36
missing is its voltage. Although00:52:39
the voltage we already have is i * r, it would be00:52:41
multiplying 6 by 2 * 6 or 6 * 2, it gives us00:52:45
12. Here 12 v are burned and we would be missing the00:52:48
power How do we get the power00:52:50
remember that we have the option00:52:53
of multiplying voltage by intensity and00:52:56
here we have the voltage remember that00:52:58
here in this single resistor00:53:00
the 12 V is burned if there are 12 vol00:53:03
multiplied by the intensity that is to say00:53:05
by 6 amps 12 * 6 gives us 72 and the00:53:10
corresponding unit the power that00:53:12
is the watts I lost a myth I check to00:53:15
see how we are doing Yes we are going well perfect Yes00:53:18
72 W would be the total power of this00:53:21
circuit eh elementary that corresponds to00:53:25
this circuit in parallel here they are00:53:27
then for this resistance Well, the00:53:30
four data that we need, its voltage,00:53:32
its resistance, the intensity of the00:53:35
current and the power, let's say that it is00:53:38
spent or that it is invested there in that00:53:40
resistance. Now we are going to return and00:53:43
pay attention to the following in a00:53:45
parallel circuit here The key comes. We already saw00:53:47
how the total resistance is obtained,00:53:49
that is, with the addition of the inverses, eh,00:53:52
multiplicatives of the00:53:54
partial resistances, but now comes a00:53:56
very interesting characteristic in a00:53:58
parallel circuit, the total voltage, that is,00:54:02
the one supplied by the Source, will00:54:04
be the same amount that is spent in each of00:54:08
the partial resistances. Be careful with this00:54:11
information, it is very important. It turns out that of course,00:54:14
understanding it, eh, with this thing about00:54:15
cyclists, if here from the00:54:18
Source here with let's say00:54:20
a current intensity of00:54:23
6 amperes comes out of the Source, which That's what he gave us,00:54:25
let's say there are six cyclists, these are00:54:28
six cyclists. When they get here, they reach00:54:30
a point where they find two paths,00:54:32
then they say, Well, along these two00:54:34
paths, I'm going to find two00:54:36
obstacles. And this is when we say,00:54:38
well, something happens that would be natural, that00:54:41
is, where the obstacle is smaller,00:54:44
a greater number of cyclists will go.00:54:54
There will00:54:56
be more cyclists and that is what is00:54:58
happening here in the circuits. It turns out that00:55:00
in the end, due to the minor obstacle, which in00:55:02
this case would be the three omios.00:55:05
Well, more current is going to pass through here00:55:07
than over here, more loads decide to go.00:55:10
electric yes larger group of00:55:13
cyclists for Well because they have an00:55:15
easier obstacle but it turns out that in00:55:17
both obstacles we say eh eh It doesn't00:55:20
matter which one How big is the group00:55:21
of cyclists they all carry let's say the same00:55:24
amount of food ation So in the00:55:26
end they all go to spend here the same00:55:28
that they received here at the Source Yes, so you can00:55:30
understand that. So in each00:55:33
resistor, look at what it says here, the00:55:35
voltage in each of the00:55:37
partial resistors because it will be equal to the00:55:39
Total voltage, which is what00:55:41
we practically have here At the entrance I mean I repeat00:55:43
here the cyclists come here they come here00:55:45
with their we say that the voltage is 12 not00:55:48
12 V they come here at this point here00:55:50
they come with their 12 V and when they each take00:55:53
their path well then those 12 vol are00:55:56
burned here and they also burn here Yes,00:55:59
in that case the voltage is not divided,00:56:02
what is divided remains the same What is00:56:05
the current, as we are going to see00:56:06
below Look what happens here if I00:56:09
want to find the intensity of the00:56:10
current By Ohm's law I divide voltage00:56:13
between resistance then here voltage00:56:16
between resistance 12 I divide by 300:56:19
gives me 4 amps and here voltage between00:56:23
current intensity00:56:25
Sorry excuse me voltage between00:56:27
resistance 12 / 6 gives me 2 I'm going to00:56:30
write it here 2 amps There it is look00:56:34
what happened to you to say00:56:36
six cyclists leave from here yes this is where00:56:39
six cyclists come this way00:56:41
here the six cyclists arrive What happens it00:56:44
turns out that a group of four cyclists00:56:46
goes this way and a group of two00:56:48
cyclists goes this way why this is where00:56:50
they go more cyclists because they are going to00:56:51
find a smaller obstacle, that is, this00:56:54
obstacle is 3 ohms while00:56:56
this one is 6 ohms. So00:56:59
the cyclists already know, of course, at the end the00:57:01
smallest group Eh yes The smallest group is00:57:04
going to go through the obstacle greater yes for00:57:06
the more difficult obstacle over there take let's00:57:08
say a smaller group of00:57:10
cyclists is going is what is happening but the00:57:12
voltage that they are burning in each00:57:15
of those obstacles is the same the same one00:57:17
that they bring here yes at the entrance let's say of00:57:20
the bifurcation Yes when they are presented00:57:22
Like those two paths available there00:57:24
So then they are going to burn that guaranteed voltage00:57:26
in both in both00:57:28
options in both obstacles But00:57:30
then you already know the amount of00:57:32
current that is, the amount of00:57:34
electric charges is going to be obviously, let's say00:57:37
inversely proportional. to the00:57:39
resistance and we are seeing it in the00:57:40
formula No, if I solve for the intensity00:57:43
Here it is, look, intensity is voltage00:57:45
over resistance as we saw. Now here we00:57:48
clearly see the intensity and the00:57:50
resistance are inversely00:57:51
proportional to the greater the resistance, since the00:57:54
lower the intensity since the voltage00:57:56
remains constant no That is, if this B00:57:58
remains constant and this r increases00:58:01
Then the value of I decreases00:58:03
So you already know the greater the resistance00:58:06
Here I have 6 ohms Here I have 3 ohms at the00:58:09
greater resistance Well, I have a lower00:58:11
current intensity of course00:58:13
only two left here cyclists00:58:15
while four cyclists left here00:58:17
Yes so that I understand it in00:58:19
those terms so it is very important to00:58:21
keep in mind that the voltage remains the same00:58:23
in the parallel circuits the00:58:25
voltage that remained the same in the00:58:27
series circuits the current00:58:29
Remember that in the circuit In series, the00:58:31
current must pass through all the00:58:33
resistors connected in series00:58:35
while here what remains the same00:58:37
is the voltage. The voltage supplied by00:58:39
the Source is burned in each of the00:58:41
resistors connected in parallel and of00:58:44
course something that we can also ensure00:58:46
here is that the total intensity yes the00:58:49
total intensity eye for the circuit in00:58:52
parallel because it will be the sum00:58:55
of the partial intensities There it is, look00:58:58
let's say that there were n00:59:00
resistors connected in parallel because00:59:03
the intensity in each of them is00:59:05
added to in the end give me the intensity00:59:07
totally clear here we can see it here00:59:09
I have eh 4 amps here I have 200:59:12
amps I add those two amounts And what is00:59:15
it giving me Well the 6 amps that00:59:17
are the ones that come out of the Source00:59:18
correspond here to what the00:59:21
elemental circuit was okay So00:59:23
Look, how it changes a little bit, not in00:59:25
the series circuits, what was00:59:29
added were the resistances, not the00:59:31
resistances, and also the voltages. The00:59:33
sum of the voltages or the sum of the00:59:35
resistances gives me the total resistance00:59:37
or the total voltage and there. The intensity00:59:39
was the same, now here00:59:41
the roles are changed a little. What remains the00:59:43
same is the voltage and what is added,00:59:45
let's say calmly, are the00:59:47
intensities. What you have to be00:59:48
careful with in the addition is with the00:59:50
resistances because you already know that they00:59:52
add up. They are the inverses, yes, the inverses,00:59:54
those multiplicative or reciprocals, what do00:59:57
we have left lacking in power? Let's01:00:00
calculate the power in each of these01:00:03
resistances in those01:00:06
places. Let's remember that power is01:00:08
obtained by multiplying voltage by01:00:10
intensity. Yes, we apply the01:00:12
power formula that It is voltage times intensity and01:00:16
then we go to each place to01:00:18
multiply these two these two01:00:19
parameters here the voltage How much is it01:00:21
12 V the intensity is four amps01:00:25
12 * 4 gives us 48 W Here is 48 W is what is01:00:30
spent here and in the other01:00:33
we multiply voltage by intensity01:00:35
here the voltage is 12 vol the intensity01:00:38
is 2 amps 12 * 2 is 24 let's01:00:41
write it here it is 24 W in the end What01:00:45
we find is that the sum of the two01:00:48
powers 48 + 24 Well it gives us 72 W Here01:00:53
It is that it was the total power if what01:00:56
we calculated in the elementary circuit, in the01:00:59
end what we found is that in the01:01:00
parallel circuit the total power01:01:04
of this entire circuit will be the01:01:07
sum of the partial powers, yes01:01:09
I repeat Well, if there were n resistors01:01:12
connected in parallel at the end because I01:01:15
simply determine the power in01:01:17
each of them and do the sum the sum01:01:20
well don't worry without doing the01:01:22
inverse thing any of that the sum as and01:01:24
current And in that way I obtain the01:01:26
total power for that circuit that in01:01:29
This case has its resistors01:01:32
connected in parallel so Ready,01:01:34
this way we have already solved the01:01:37
parallel circuit we already have in01:01:39
each of the resistors its four01:01:41
characteristics which is eh resistance01:01:44
current intensity voltage and01:01:47
power and with that we finish So01:01:50
the second example here we can01:01:52
Delete this and and we go now to01:01:56
the last one which is the mixed circuit,01:01:58
let's then draw it and01:02:01
solve it obviously do the whole01:02:03
process until we solve it completely01:02:07
then let's01:02:09
see let's see how the transmission goes01:02:12
Yes we're fine now It's been an hour, I01:02:15
knew that this video was going to be quite01:02:17
long. But well, it's like a summary, not01:02:20
of the whole topic of01:02:22
electrical circuits, I repeat, starting from the01:02:23
theoretical basis and showing in this case the01:02:26
three situations, that of the01:02:28
series circuit, the circuit. in parallel and now the01:02:30
mixed circuit for the mixed one we are going to01:02:34
make the following drawing which01:02:35
is the one that appears precisely in the01:02:37
thumbnail of the video we are going to do it01:02:40
here and see here yes I am going to need a01:02:43
little more01:02:44
space to be able to wow because01:02:47
this drawing is going to present01:02:50
some changes to see here we have a01:02:52
resistance we have over here we are going to01:02:55
do it like this we have one here like this01:02:58
over here we have one like this and another01:03:03
over here yes let's wait and see that01:03:07
Ah so that it fits all the01:03:09
information so let's see This is the01:03:11
circuit that appears in the thumbnail of the01:03:13
video we have here a source a01:03:15
generator that supplies 15 V Yes here01:03:19
we are going to place the voltage 15 V the01:03:22
resistors that we have here this one is01:03:24
201:03:26
ohms We also have one of 4 ohms01:03:29
here, this one is 4 ohms and the two01:03:33
below are 7 and 5 ohms, this one here01:03:36
is from s Sorry mythical, this one here is 701:03:41
ohms so 7 ohms here and this one01:03:45
here is 5 ohms There They are01:03:47
So let's say they ask us to solve this01:03:50
circuit that is now called mixed Why01:03:52
will it be mixed because it has resistors01:03:54
connected in series and also in01:03:56
parallel for example look at these two01:03:58
here these two resistors that are01:04:00
here in this in this section the circuit01:04:02
let's say from this point up to this01:04:04
these two resistors that we see here01:04:06
are in series and these two now we are going to01:04:09
see how it becomes one and that with01:04:11
this one here are going to be in parallel and01:04:14
then Those two in parallel are going to01:04:16
form another one that in turn with This one here01:04:18
is going to be connected, they are going to be in01:04:20
series. Yes, then that is why it is called mixed01:04:22
because it has both of the above, that is,01:04:24
it has some connected in parallel,01:04:26
others connected in series, so what01:04:28
we have to do in this case is to01:04:30
gradually transform it. the circuit until we01:04:34
take it to one that is elementary,01:04:36
so let's see the first step in this01:04:39
case, it will be to convert these two to a01:04:42
single resistor. So let's do it01:04:44
here. I'm going to try to01:04:47
keep those drawings the same size so that they01:04:50
fit here, there are four. Here we make01:04:55
the01:04:57
generator here here there are also four Aha01:05:02
let's go down here we make the little01:05:05
drawing of the01:05:06
resistance here it comes01:05:09
here Okay so here01:05:11
we go up here we have this one01:05:15
here and this one down here let's see This is the one01:05:18
that we are going to convert here into a01:05:20
alone Look at this one01:05:22
here, the one we have here is going to be the01:05:25
result of these two that I have here,01:05:27
as we see, these two are in series and01:05:29
let's remember that the resistances when01:05:31
they are in series are added together, common and01:05:34
current, to find the01:05:36
total resistance. In other words, that at once this01:05:38
resistance here is the result of adding01:05:40
these two that are in series Well, it will be 701:05:43
+ 5 12 ohms Yes, this one is 1201:05:47
ohms, this one up here is the 401:05:49
ohm one that does not present any change,01:05:52
this one here is 2 ohms does not change either01:05:55
And this is the source that is01:05:57
supplying 15 V So look That is01:06:01
like the first the first stage that is to say01:06:03
go from that circuit to this one where the01:06:05
change has occurred here in these two01:06:08
resistors that are connected in01:06:10
series and that They have produced this one here01:06:12
let's continue So now let's see I'm01:06:16
going to try to make sure it fits01:06:18
here so I can do01:06:20
the accounts down here now Yes to leave space01:06:23
then let's see let's move on01:06:25
to a circuit now Yes here I It01:06:29
fits, yes, here I'm going to try to make it01:06:31
fit, we're going to do it this way.01:06:35
Here is the generator over here we have. So01:06:39
this like this, it comes this01:06:45
way and01:06:47
here, let's see these two that I have here, they are01:06:50
going to form a01:06:52
resistance here, this one comes through. here and01:06:56
so attention So these this01:06:59
is still 15 V here 15 V here in the01:07:03
generator this resistance is this one01:07:06
here that is still 2 ohms we are going to01:07:08
place the two here so that I01:07:10
can get out Aha And this one that I have here01:07:13
Attention, this resistance is going to be the01:07:17
equivalent or the sum of these two, but01:07:19
be careful that they are in parallel here where01:07:22
we must take into account the sum01:07:24
of the reciprocals. So let's01:07:26
do the math here, let's add and01:07:28
see to find this resistance we are going to01:07:30
call it provisionally RT01:07:32
provisionally Yes because it is not the01:07:34
total yet so this RT01:07:37
total resistance eh comes from adding01:07:40
the reciprocals of these two that is to say01:07:44
1/4 + 1/1 yes There it is 1/4 + 1/1 and01:07:50
attention everything this raised to -101:07:54
Remember that I must invert this01:07:57
result to be able to obtain the01:07:58
total resistance of these two01:08:01
resistors that are connected in01:08:03
parallel So we are going to proceed with01:08:05
the addition of fractions01:08:07
1/4 I can multiply it I can01:08:09
amplify it by multiplying by three up01:08:12
and down then I will have 3/1 if I01:08:15
multiply by three above I multiply01:08:17
by three below I have about 3/1 so I01:08:20
can add it easily with 1/1 that is to01:08:23
say that we are left with the sum of01:08:25
fractions eh homogeneous we do the sum of01:08:28
3/1 + 1/1 that would be 4/1 if all this01:08:33
to the -1 and we apply here the effect01:08:37
of the exponent -1 which what it does is01:08:39
invert the fraction we would get like this01:08:42
12/4 and 12 gave 4 gives us 3 that is, in the01:08:47
end this resistance here that we have01:08:49
provisionally called RT is worth 301:08:52
ohms. So we are going to remove this01:08:54
from here, we are going to remove this from here and01:08:57
we are going to write down the result. Don't worry,01:09:00
the video is recorded. Don't01:09:02
worry here. It has given three ohms,01:09:04
look, I repeat, this three ohms is the01:09:08
result of the sum of these two01:09:11
resistances connected in parallel, which01:09:13
I repeat is the sum of the reciprocals,01:09:16
that is, of the multiplicative inverses.01:09:19
Sorry for a01:09:22
moment, let's01:09:24
refresh our throats and now,01:09:27
look now. What we do is go from01:09:30
here, I'm going to do it here, this is the01:09:33
sequence, not the original circuit, which is01:09:35
mixed, then we go to this one, which is when01:09:38
these two Sorry, these two resistors01:09:39
in series form this one. Then we move on to01:09:42
this other drawing where these two01:09:44
resistors I have these two01:09:46
that are connected in parallel and look what01:09:48
I have here two resistors01:09:50
connected in series. The cyclists leave01:09:52
here and pass through this obstacle then01:09:55
they arrive here at this other obstacle to01:09:57
return to the Source these two01:09:59
resistors are connected in series so01:10:01
They are going to form an01:10:03
elementary circuit for me. Here I am going to get01:10:06
to what the elementary circuit is, which is01:10:09
where I am going to do the analysis to come01:10:12
back to me then. Here I am going to01:10:15
draw it this way, there we have01:10:18
then what is the total resistance01:10:21
of these two What I have here is that as you can see01:10:24
they are connected in series and when they are01:10:26
in series it is much easier, let's not01:10:28
remember that it is the common and01:10:29
current sum of the resistances we have 201:10:32
ohms + 3 ohms that gives us 5 ohms and01:10:37
here in the source in the01:10:39
generator, let's remember that we have a01:10:42
voltage that they supply to us that is 1501:10:45
V, so01:10:47
let's see in that case, Aha, we're doing well,01:10:51
then, we have a total resistance,01:10:53
eye, this one. Yes, it would be the01:10:56
total resistance of this original circuit because01:10:58
let's remember that here we have already reached the01:11:00
elementary circuit, which It has a single01:11:03
resistor with its conductor and its01:11:05
generator, generator, conductor,01:11:07
resistance, these are the three components,01:11:10
remember, of an elementary circuit. So01:11:12
this one here is going to be the01:11:15
total resistance of this entire circuit01:11:18
that we have here. Here there were four01:11:19
resistors in total, two connected in01:11:22
series. well these go in parallel and in01:11:24
turn this here is connected in01:11:26
series that is why it is called a mixed circuit.01:11:29
So now that we are here we are going to calculate01:11:32
the missing elements I have voltage01:11:34
I have resistance I come to Ohm's law01:11:37
I have voltage and resistance I can01:11:39
know what it is the intensity of the01:11:41
current then let's see the intensity of01:11:43
the current remember that it is voltage01:11:45
over resistance if it comes out of the01:11:48
triangle we are going to replace the01:11:50
values the voltage is 15 15 V01:11:54
over the resistance that has given us 501:11:57
ohms and the total resistance of the01:11:59
circuit 15 over 5 gives us three three what01:12:03
amperes why amperes Because we are01:12:05
calculating the intensity of the current01:12:08
So we already know how much it is here it is01:12:12
look I have here a01:12:14
current intensity of 3 amperes that01:12:17
will logically pass through here so here I have01:12:19
3 amperes So I already know how much the01:12:22
cyclist's lot is. So to speak,01:12:24
we already know that 3 amps come out of the Source, they are going to come out01:12:27
of here too.01:12:29
Now we are going to return once we01:12:32
calculate the elementary circuit we01:12:34
are going to go back until we get here to01:12:36
what It was the original circuit where01:12:38
we are going to record in each place01:12:41
their respective values of01:12:43
resistance,01:12:45
current intensity, voltage and power. So01:12:47
we have already done the01:12:49
calculation of the current intensity here01:12:51
and we are still missing the calculation of the01:12:54
power the power that we remember here01:12:57
is obtained by multiplying voltage01:12:59
by01:13:00
intensity power is voltage by01:13:03
intensity So how much is the voltage01:13:05
here in the elementary circuit is 15 V01:13:08
let's remember that those 15 vol are burned01:13:10
Here also if here we have the 15 V01:13:12
we are going to notice by here 15 V then 1501:13:16
V multiplied by the intensity of the01:13:19
current we said that 3 amperes circulate here01:13:22
So in the end Well, what01:13:25
gives us 15 * 3 is 45 and the unit of01:13:29
power is watts So01:13:31
we already have 45 W which would be the total power01:13:37
here of the elementary circuit s 45 W01:13:40
So look here I already have the four01:13:42
data I have resistance I have intensity01:13:45
of the current I have the voltage and I have01:13:47
the power and I already know what is the amount01:13:50
of current that circulates or leaves01:13:52
the Source So now01:13:55
we do Let's start to return to see01:13:58
from here we go here attention from here01:14:01
a circuit that was in series returns01:14:03
let's remember what is maintained In a01:14:05
series circuit the current is maintained01:14:07
if the current is the same if01:14:09
the group of cyclists leaving the01:14:11
Source it runs through the entire circuit when01:14:13
its resistances are connected in01:14:16
series So let's remember if from here to01:14:18
the Source Here it is Look 301:14:20
amps come out Here it is the intensity01:14:23
is 3 amps then those 301:14:27
amps pass through here 3 amps pass through here01:14:29
and they pass through here if not They have01:14:33
another option, there is only one path. Yes,01:14:36
then on the path it is an obligatory step.01:14:38
This first obstacle and this other01:14:41
obstacle we now have, so what are01:14:43
the intensities of the current in01:14:46
each of these two places, now what01:14:48
remains Sorry, with that, what? We can01:14:50
find if I already have resistance and the01:14:53
intensity I have resistance I have01:14:55
intensity I can find voltage01:14:57
by applying Ohm's law So what01:15:00
do I do here it is look voltage is i * r01:15:03
I multiply the intensity by the01:15:04
resistance 3 * 2 it gives me 6 it means01:15:08
that they are consumed here 6 v and here 3 * 301:15:12
gives us 9 9 V applying I repeat Ohm's law01:15:16
I by r I multiply i * r intensity by01:15:19
resistance here in each of these01:15:21
places in each of those uh devices01:15:24
let's say connected And that way01:15:26
I get the voltage that burns in01:15:28
each one of them and I can verify01:15:30
something that we saw now that we saw01:15:33
previously That the sum of the01:15:35
voltages well gives me the total voltage of01:15:37
course look Here I have 6 6 V + 9 V 9 + 601:15:42
gives me 15 15 V, which is what01:15:45
the Source provides me, means that01:15:46
we are doing well. Yes, in that way, we are01:15:49
verifying that we are checking each stage01:15:51
of the process because in order not to01:15:53
suddenly present an error, we can01:15:56
then also calculate the power01:15:57
by multiplying voltage by intensity, eye01:16:00
voltage by intensity in each place01:16:02
so here when will the power be?01:16:04
I multiply the voltage by the intensity01:16:06
of the current For 3 amps 6 V times 301:16:10
ampi 6 * 3 it gives us 18 18 W would be Then01:16:15
the value of the let's see if I'm01:16:18
getting this01:16:19
there I don't think I can't get it out,01:16:22
I'm going to put it here so it's01:16:24
18 W Yes, I knew that this exercise01:16:28
was going to take up a lot of space here on01:16:29
the board here then 6 * 3 18 W and01:16:33
here I multiply voltage by intensity01:16:35
voltage by intensity 9 * 3 gives us 2701:16:39
27 W. There it is, I can check if we are doing01:16:43
well. I have 18 W here, 27 W here. I do the01:16:48
sum and we find that this gives us 45 W, that is, let's01:16:52
say the Total power that01:16:54
we had determined for the01:16:57
elementary circuit. So we are doing well. Now from01:16:59
this this stage we return to this one01:17:02
here, notice that this Sorry for a01:17:04
moment this here this would be repeated01:17:08
here that is to say this does not really change So that01:17:10
at once we could bring it here not to01:17:12
see for that for this resistance of01:17:14
2 ohms I have 3 amps let's01:17:17
write here at once 3 amps01:17:20
we have 6 V that is consumed here 6 v and we01:17:25
also have 18 W let's place it01:17:28
here 18 W all this for this01:17:31
2 ohm resistor I repeat this01:17:34
remains here Exactly the same If it does not01:17:37
present any change at the end, it is this one01:17:39
that we have here where we do have to be01:17:41
careful is what happens down here,01:17:43
look because this resistance now01:17:46
becomes these two and in turn this one01:17:49
becomes these two here,01:17:51
so let's see from here to here We are going to01:17:54
return to two resistors that are01:17:56
connected in parallel and attention, what we01:17:59
saw previously in the circuits with01:18:02
resistors connected in parallel,01:18:04
we saw that the voltage in each of01:18:06
them is the same, the voltage is01:18:09
exactly the same. So what do we do01:18:11
here, look at this point or here let's say at01:18:14
the input of the resistor or at its01:18:17
output, however you want to look at it,01:18:18
any of the two points can be01:18:20
the input, we have a voltage of nu01:18:23
volts there, which would be So the one we01:18:24
have here or Also here, yes, that is, those01:18:28
two points, imagine that are these two01:18:30
here So in the end here come 901:18:32
vol that are going to be distributed here 9 and nu9 yes01:18:36
because the voltage I repeat remains01:18:39
the same in each of the resistors01:18:42
there we have 9 V what what is going to01:18:45
change So as we see now the01:18:47
intensity of the01:18:49
current we know that 3 amps pass through here01:18:52
so here come 301:18:55
amps that of course come from the01:18:56
Source well in fact I can01:18:58
draw that at once here No yes the01:19:00
same TR amps from here those this01:19:04
intensity of 3 amps Here there are 301:19:07
amps that are the ones that pass through here01:19:09
look yes here come the 3 amps here01:19:11
come 3 amps a little group is going to go01:19:13
here and another little group is going to go01:19:15
here let's see here I have 4 ohms here I have01:19:19
12 ohms So for here where there is01:19:21
less resistance01:19:23
because the largest group is going to go.01:19:25
Yes here we are going to have greater01:19:27
current than here so let's see01:19:29
how that is done. What we do is to01:19:32
calculate the intensity of the current01:19:33
in each place we apply the law of Ohm01:19:37
intensity which is voltage over01:19:39
resistance B over r There it is, look01:19:42
then here in each place I divide the01:19:45
voltage by the resistance we divide 901:19:49
/ 4 let's see that I already did the calculations01:19:51
here so that we can save01:19:53
time that gives us then01:19:58
eh01:20:00
2.25 A see 9/4 of course half of 4at01:20:03
would be 4.5 half of 4.5 is 225 Ah01:20:07
so we have01:20:08
225 amperes 2.25 amperes here on this01:20:13
side here and here we would have to divide01:20:15
voltage by intensity that is to say 9 / 1201:20:19
that division 9 / 12 gives us eh01:20:24
0.75 of course 9/1 would be 3 cu4 no I01:20:29
mean when doing the simplification Sorry a01:20:33
myth when doing the simplification of nu901:20:36
voltage between resistance of 9 / 12 per01:20:41
9 / 12 we take third we are left with 3/4 which01:20:44
in the end is01:20:47
0.75 amps, of course, what we had01:20:49
said, no, that is, here, this way, this01:20:52
way where there is less resistance because01:20:55
we have greater current, yes, here01:20:57
more cyclists go 2.25 ampi while01:21:00
here we have a01:21:03
greater resistance, here it is 12 ohms because we have01:21:05
a smaller current smaller number01:21:08
of cyclists in this case01:21:10
0.75 amps and what we can what01:21:13
we need to find here in each of01:21:15
these sites Well, it will be the power and01:21:17
power is voltage times intensity01:21:20
so I multiply in each site the01:21:23
voltage by the current or by the01:21:25
intensity of the current 9 * 2.25, let's01:21:28
see what I calculated, I had already done it, it01:21:29
also gives me01:21:31
20.25, that is, here in this place 20.25 W are burned01:21:34
or spent.01:21:36
There it is01:21:39
20.25 And in the other we have 67501:21:43
multiplying voltage by intensity01:21:45
multiplying here 9 vol times01:21:49
0.75 we said that it gives 6 7501:21:55
6.75 W of course in the end what we can01:21:58
verify there is that the watts that are01:22:01
spent here plus the watts that are spent01:22:03
here which would be 20.25 + 6.75 that gives us a01:22:08
total of 27 W you see Here are the ones that01:22:11
We had here in this resistor01:22:14
20.25 +01:22:16
6.75 it gives us those 27 W which was what we01:22:19
had determined here remember this01:22:21
this resistor01:22:23
is the equivalent of these two that I have01:22:25
connected in parallel So now01:22:27
we have for each of these two01:22:29
sites its four components Yes, what01:22:32
is resistance, intensity, voltage and01:22:35
power Now we are going to return01:22:38
to finish what the original circuit is,01:22:40
those data here are maintained.01:22:43
Here we are going to place them 4 ohos 9 vol01:22:47
we are going to place here 9 vol that are01:22:50
spent in this resistance we have there01:22:52
2.25 amperes we are going to write them01:22:55
here01:22:57
2.25 amperes and the watts which are01:23:02
20.25 we are going to write them here01:23:06
20.25 W well you When you do this01:23:10
try to make the drawing bigger or as01:23:12
big as possible on your graph paper01:23:15
hopefully because they look This01:23:18
starts to fill up with numbers if in01:23:20
each of these places in each01:23:21
resistor when you are not01:23:23
recording the other data. No now01:23:27
what we need is to go from this01:23:29
resistor, let's say it has these two01:23:32
points to these two points here. which01:23:35
we remember were connected in series And01:23:38
let us remember that when the resistors01:23:40
are in series what remains the same01:23:43
there is the current yes the cyclists01:23:46
who come this way are uh01:23:49
0.75 amps Yes then you have to01:23:53
go through this obstacle and also through01:23:54
this one here or So the intensity of01:23:56
the current in each of them is going to01:23:58
be 0.75 amperes, let's write it01:24:02
here as 0.75 amperes and here also01:24:06
0.75 amperes. If the current01:24:09
remains the same when the resistors01:24:11
are connected in series, remember that the01:24:13
cyclists must01:24:15
necessarily go through Those two obstacles01:24:17
have no further path and so what01:24:19
we do now is calculate the voltage here in each01:24:21
place if I already have intensity01:24:24
and resistance then I multiply these01:24:26
quantities to find the voltage here01:24:29
in each of these places let's see01:24:32
then we multiply cco That is the01:24:35
resistance here it is 5 the current is01:24:38
0.75 it would be 5 * 075 that would be 5 * 3/401:24:43
it would be 15/4 that gives us to see a01:24:46
momentary 15/4 it is Aha 201:24:51
point Sorry01:24:53
3.7501:24:57
3.75 vol of course it would be 15/4 it would be half01:25:01
of 7.5 Aha 3.75 V There it is and here01:25:06
we also multiply the intensity by the01:25:08
resistance 0.75 * 7 that gives me01:25:13
5.25 Well I have already done the calculations to01:25:16
speed this up01:25:18
5.25 Sorry Excuse me Excuse me volts01:25:22
are not watts but volts because I am01:25:24
finding voltage There are volts yes01:25:27
multiplying I by r in each of01:25:29
these sites and what we are missing01:25:31
to finish is the power in01:25:35
each of these two sites and the power.01:25:37
Remember that it is obtained by multiplying01:25:39
voltage by intensity, for example in01:25:42
this one here I would multiply the voltage01:25:44
3.75 for the intensity which is01:25:47
0.75 and that gives me two point Sorry for a01:25:51
moment two01:25:53
point01:25:55
8125 It's 2 points01:26:00
8125 W yes I repeat multiplying voltage01:26:04
by intensity I multiply 3.75 vol by01:26:08
0.75 amperi it gives me this 2.8125 W and here01:26:13
we do the same we multiply voltage01:26:16
by intensity and that gives me01:26:21
3.93 7501:26:25
3.9301:26:27
75 W yes, remember watts is the unit of01:26:30
power, we multiply 5.25 V by the01:26:34
intensity 0.75 ampi and it gives me that01:26:37
quantity01:26:39
3.9375 if we add those two01:26:42
quantities at the end Well,01:26:44
this has to give us01:26:46
6.75 W that is You can check, the01:26:49
sum of these two is done and it has to give us01:26:51
6.7 35 W, which was the power that we01:26:54
had determined here in this01:26:56
resistor, which is the equivalent of01:26:59
these two that are connected in series01:27:02
and now we are finally done with this,01:27:06
look. We already have the01:27:08
mixed circuit completely resolved, that is,01:27:12
remember that the only information01:27:13
we knew was the voltage01:27:15
supplied by the source and the resistors01:27:18
that are connected, some in series,01:27:20
others in parallel, that's all01:27:22
we had, but look at the process that must be01:27:24
carried out. to the01:27:25
elementary circuit and then go back to be able to01:27:29
find out in each place Yes, in each01:27:32
where each resistor connected or01:27:34
each electrical device connected is so01:27:37
see what happens in each one of them What01:27:39
is its resistance What is its intensity01:27:41
What is its voltage and what It is the power.01:27:44
Another thing that can be done01:27:46
for the mixed circuit would be to add all01:27:49
the powers, for example, here add 1801:27:52
W eh + 20.25 w + 2.8125 w +01:27:59
3.9375 w. The sum of those four01:28:03
powers in the end must give me this01:28:05
one. I have here the 45 W. That is, for the01:28:08
circuit it does not matter if it is in series or in01:28:11
parallel or mixed, the total power01:28:14
there is adding all the powers of the01:28:18
devices or artifacts that01:28:20
are connected, it does not matter how01:28:22
they are connected, as you saw, they can01:28:23
be in series can be in parallel01:28:25
or they can be mixed, simply what01:28:27
I do is add all those powers of01:28:29
each of the connected devices and it01:28:31
gives me the total power of that circuit01:28:34
so good with this Now I do01:28:37
finish the explanation I knew I was going01:28:39
to be long look at almost an hour and a half01:28:42
of01:28:43
transmission Remember that this signal is01:28:46
to indicate that the explanation has ended01:28:48
also the invitation to subscribe01:28:50
to the Channel and Now I am going to read some01:28:54
messages Now to finish to close01:28:57
today's transmission I knew that It was going to01:28:59
be a bit long but hey, what01:29:02
I wanted to do was explain the topic of01:29:04
electrical circuits, I repeat, to be able to01:29:07
share with you what I01:29:08
learned 33 years ago,01:29:11
imagine when I was 13 or 1401:29:14
years old, I was in ninth grade.01:29:17
I mean, the fourth grade of01:29:19
high school here in Colombia and that was01:29:22
when I learned this for the first time and01:29:24
I repeat, I thank my physics teacher,01:29:26
Professor Eutimio Ruiz, who01:29:29
taught me this way with the example01:29:31
of the cyclists, which is here. the01:29:33
power zone that what it spends01:29:36
that each resistance is an obstacle and01:29:38
of course in each obstacle it spends a01:29:41
part of its energy not of what it obtains01:29:43
here in the source in the01:29:45
power zone so it really is01:29:47
a good way To understand how these01:29:50
circuits work What things to take into01:29:53
account, don't remember for01:29:54
series circuits How resistances are added What01:29:57
is it that keeps01:29:59
parallel circuits the same How01:30:01
resistances are added What is with reciprocals01:30:03
What things remain the same and Well then01:30:05
when it is a mixed circuit that is a01:30:07
little more complex but you already know01:30:09
what to do is little by little to01:30:12
drive it to a circuit that is of an01:30:14
elementary type Now yes then I am going to01:30:19
read here quickly I hope that They01:30:20
have behaved well in the chat01:30:23
there I have my moderators helping me01:30:25
really thank you because well I see01:30:28
that there are blocked messages look I01:30:31
also thank Nicole in the super01:30:33
chat Thank you very much Nicole for your01:30:35
contribution to support my project01:30:38
Thank you for that kindness eh Let's01:30:41
see here I'll go back a little bit01:30:44
yes Unfortunately, whoever doesn't know how to01:30:46
behave in the chat has a01:30:48
temporary warning that is like a01:30:50
yellow card And well, if it continues or if it's a01:30:54
first, the message already crosses the line01:30:56
because it has a card red guys, that is,01:30:58
there I ask you, as always, for good01:31:01
behavior. Remember that this is an01:31:02
Education channel. Yes, where I always01:31:05
hope that your behavior is up to01:31:07
par. No. In other words, we want a01:31:08
healthy community, a respectful community01:31:12
that knows how to express itself in good terms.01:31:14
through that space Well, what is the01:31:16
chat for you? Hey, Leandro01:31:19
Maldonado, teacher, help by pen, the01:31:22
potential difference between point a and b01:31:24
of the circuit. Well, yes, it is another way of01:31:26
asking the question. No, sometimes, for example,01:31:28
they can tell you an example. What is it? the01:31:32
potential difference between point a01:31:35
and point B,01:31:37
imagine if they can tell you in that01:31:39
circuit the01:31:41
potential difference between a and b is calculated, then of course I01:31:43
have to get to practically01:31:45
this point, look here Here when I01:31:48
know that is point a and that is01:31:50
point b and here when I do the01:31:52
analysis I realize that the01:31:54
potential difference is 9 V that is,01:31:56
between those two points a and b yes of the 1501:31:59
V Well, here a total of 901:32:02
vol has been spent Of course because here six have already been burned01:32:04
Not here you can see 6 V if the01:32:07
cyclists came here they burned 6 V of their01:32:10
energy And here between points b and a or a01:32:13
and b well they burn the rest which is the 9 V01:32:16
but we got them here that's why we have to01:32:19
do this whole process So don't think01:32:21
that This is to fill space here,01:32:23
it is not because the entire analysis has to be done01:32:25
little by little, it has to be reduced01:32:28
until it is brought to the elemental circuit and01:32:30
in this way, I now determine01:32:32
between any two points that they01:32:34
ask me what happens between the two of them, that is, What01:32:36
type of resistors I have connected And01:32:38
that way I can establish, well,01:32:40
what they are asking me for in this case, well,01:32:41
the voltage here, eh,01:32:46
potential difference is equal to voltage, says Juan01:32:48
Montenegro, there are exactly two ways in01:32:52
which it can be known, does Darwin say?01:32:54
López I had already forgotten, teacher,01:32:56
thank you very much, well, with great pleasure,01:32:58
Darwin, what01:33:00
better thing are they asking me to repeat01:33:03
everything, please don't worry, now that01:33:05
when the transmission ends, the01:33:07
video remains so that you can repeat it all01:33:09
in fast motion, in slow motion, you01:33:12
can pause you already know that here it is01:33:15
at your entire disposal Thank you Mario01:33:18
Denis for your message Thank you also01:33:20
Pablo is eh Here too Rina table01:33:24
Thank you very much Rina for your message I am01:33:26
glad that you liked the class if01:33:29
this was a complete class let's say with01:33:31
some theory with examples with01:33:33
exercises Exactly You have to practice says01:33:36
Toño Ascorra exactly with this it is a01:33:39
matter of practice also like everything01:33:41
not like what is mathematics physics01:33:43
well chemistry everything is pure practice pure01:33:46
exercise for one to achieve Well,01:33:49
strengthen the concepts and gain skill he01:33:52
says from Chile Alfonso Losa Cruzate,01:33:56
I should make more videos on01:33:57
electrical circuits, which is very interesting.01:34:00
Well yes, really, that is the first one01:34:02
I have done on this topic, believe me,01:34:04
excuse me because, let's say, the01:34:06
physics category was a little abandoned,01:34:09
what happens is that You will understand01:34:11
that they are more eh, the01:34:13
mathematics categories, not where I have been working,01:34:16
this one on physics. Well, yes, it has been a while since01:34:17
I have touched it. Well, I had told you that I was going to01:34:19
have some physics videos soon, and I01:34:21
am already preparing01:34:23
others on other topics, but yes. I hope01:34:26
later to be able to complement not with more01:34:27
exercises on electrical circuits, but01:34:30
suddenly a mixed one that is a little more01:34:32
complex, but look, anyway, when one01:34:35
works on the mixed circuit, one must apply01:34:37
the concepts of what01:34:39
series circuits and parallel circuits are, that is, there01:34:42
one applies everything seen above. So01:34:44
don't worry, I'm going to look for a01:34:47
way to prepare other exercises that are01:34:49
a little more elaborate, that is, with greater01:34:52
difficulty so that,01:34:55
as they say, they have a greater01:34:59
variety of exercises. Well, let's01:35:02
see here and close. Because that01:35:05
spread to us, look at a lot of terman.01:35:08
Thank you very much, Terens, for being01:35:10
connected. I haven't read your messages in a while.01:35:12
Very kind, a very special greeting there01:35:14
in Mexico. Thank you, Toño again01:35:20
says 409. Thank you for your message. I'm01:35:24
glad that the videos helped you01:35:26
to pass by. mathematics Luis01:35:28
Emilio zambrana montealto Thank you very much01:35:31
Luis Emilio for your message01:35:33
eh Alejandro Campos says that it was possible01:35:37
of course we reached the end of the01:35:39
explanation Rosario Segundo01:35:42
Thank you very much Rosario Thank you Jason peréz01:35:45
from Pasto Nariño a big hug there01:35:48
in the south of our country there in in01:35:51
grass Thank you very much01:35:54
eh says I'm sorry Robert Juárez says01:35:59
The Law of has a01:36:00
mathematical demonstration or is it more experimental eh01:36:03
Well the truth is I don't remember having01:36:05
seen the demonstration Maybe it must01:36:06
exist Or maybe it's a concept of01:36:10
how I explain that When01:36:12
the relationship is established between two variables,01:36:15
in that case, let's see, here is the law01:36:18
as we saw. What I understand is that01:36:21
a direct relationship was found between01:36:23
these two variables. I mean, there it is.01:36:25
Look, the voltage is directly01:36:28
proportional to the current yes So01:36:31
when when that direct relationship is formed01:36:33
what is incorporated is a01:36:35
constant of proportionality which in01:36:36
this case is the resistance yes in that01:36:39
way it goes from being this expression01:36:42
of what is directly proportional to01:36:44
becoming an equality and here it is01:36:46
what resistance is So in that01:36:48
way we find well here it is the other way01:36:50
around no and for r but remember that it is01:36:52
the same as r for I So01:36:54
really it is it is either of01:36:57
the two is correct due to the01:36:58
commutative property of the multiplication of01:37:00
done before starting the transmission, I01:37:03
managed to read a message from someone01:37:05
here in the chat who said Ah, the formula01:37:07
for long live Queen Elizabeth, of course. Look at it.01:37:10
Here it is if you want to learn it that01:37:11
way, long live Queen Elizabeth. In other words, there are01:37:14
ways to learn this formula just01:37:17
as there is that of a cow minus the01:37:20
integral dressed in uniform to01:37:21
learn the formula for integration by01:37:23
parts Eh well there are so many formulas that there are01:37:25
in mathematics in physics but in01:37:27
this case those little triangles are quite01:37:29
effective for learning let's say eh the01:37:33
formulas or or the clearances that one01:37:36
needs from some of those variables,01:37:38
be it voltage, intensity, resistance,01:37:40
but I repeat what I understand is that perhaps,01:37:43
through pure01:37:44
experimentation, I think, or I am01:37:46
assuming, it was found that01:37:48
there was a direct relationship between01:37:50
voltage and intensity. of the current01:37:53
and of course in the end because what leads to01:37:55
what it leads to is an equality where01:37:57
a constant of01:37:58
proportionality appears, which in this case is the01:38:00
resistance. Yes, many things in physics01:38:03
have come out like this. That is, through experimentation01:38:06
as well as when it is done a laboratory,01:38:08
not that one takes the data, the times and01:38:10
the masses, in short, and modifies01:38:13
some some parameters, takes01:38:15
notes, then takes a graph and01:38:17
finds what is the mathematical relationship01:38:20
that exists between the variables studied,01:38:22
so I imagine that it can be be01:38:25
from there that the law of om comes from. Maybe it01:38:27
should have a livelihood, well, well,01:38:29
more elaborate, the truth is,01:38:32
I don't know it, yes, I repeat, here I am bringing, look, I am doing01:38:34
an exercise for my01:38:36
memory after 33 years of something01:38:40
that I saw when I repeat, I was 13 or 14 years old,01:38:43
I'm talking to you about the year01:38:45
1986 1987, more or less when I attended my01:38:49
fourth year of high school, which was01:38:52
when I saw this topic and, as I01:38:54
told you at the beginning, I built circuits like these,01:38:57
physically, that is, on01:38:59
a table of wood that had some little01:39:02
holes and there with screws we were01:39:04
arranging the little cables.01:39:06
We made all these little cables with, uh,01:39:09
clamps with a cold cutter with pliers, if we01:39:12
gave them the shape at the ends so that they01:39:14
would look like little eyes.01:39:16
Yes, with the copper wire, well peeled And01:39:18
that way I can place the01:39:20
screws there in the speech and and do Ah something01:39:22
that I had forgotten to tell you01:39:25
is that in the circuits there are also01:39:27
switches Yes, for example here I01:39:30
can uh draw a switch that is01:39:32
made in this way no There it is, look,01:39:34
this is how a switch is drawn. In a01:39:36
circuit, that is, the switch, of course, what it01:39:37
does is suspend or allow the passage01:39:40
of current. Yes, this is how a01:39:42
switch is represented. We also made those switches01:39:44
with these little cables.01:39:46
I remember that the switch had this01:39:48
shape. It wasn't here the copper wire01:39:51
here it came this had this shape and like that and01:39:55
here it came back out or what I'm going01:39:56
to repaint this part that is repainted01:39:59
was like the the lining not of the wire01:40:02
yes because it was a 14 gauge wire or 1201:40:05
or 14 I don't remember what it was, because it was thick, it01:40:08
had to be molded with01:40:10
tweezers with pliers, it was something. Like this,01:40:14
this part here was copper that was01:40:17
given the shape of a little eye And that was01:40:19
also copper and here in this part01:40:21
From here this was where the screw came in.01:40:23
Yes, the screw came in here, and in01:40:26
turn, here is the little screw, yes, in01:40:29
turn the little screw. Well, it went to01:40:31
a board and under the board, the little01:40:33
nut was put on the screw, that is,01:40:35
it was It's very nice to be able to build01:40:37
this type of circuit on that wooden board and01:40:40
then connect this to the current01:40:42
where you had to be very careful not01:40:43
because well imagine if there was some01:40:45
error in the analysis of the circuit01:40:48
eh or in the or the moment of the assembly01:40:51
to connect because at the moment of one01:40:53
Connect to the current if there was any01:40:55
error then that would explode and that's where the01:40:58
short circuit would come you had to be careful01:40:59
but in the end I think that's01:41:01
where the01:41:04
application of mathematics and01:41:06
Physics, this teacher that I am telling you01:41:08
told us this phrase, I have not forgotten this either,01:41:10
he said electricity is not01:41:12
dangerous, it is one who is dangerous, that01:41:14
is, the human being is the dangerous one, it is the one01:41:16
who is suddenly reckless, the one who does not01:41:18
take sufficient precautions in order to be01:41:21
able to say eh get to work with01:41:24
electricity he said that and it is01:41:26
totally true. That is why01:41:28
when the design is made it does not concern01:41:31
everything that is the electrical plan or01:41:34
the electrical installation of a home01:41:35
for example, well First, some01:41:37
plans are made if all the layout is done01:41:40
well. What lengths of cable am I going to01:41:42
need? What type01:41:44
of connections are they going to be in series01:41:47
in parallel? Well, if the01:41:50
fuse box is all that, well, so that in the01:41:52
end when Now let's01:41:54
turn this on so there won't be01:41:56
any damage. Yes, everything works01:41:58
perfectly. In the end, that's what it really is, or it01:42:00
's really the electricity itself. Yes, it01:42:03
's not dangerous. The reason my teacher was01:42:05
dangerous.01:42:07
eh the01:42:10
necessary precautions to be able to Well work with01:42:13
her that in the end well she is at01:42:15
our service we don't have to know her01:42:17
is to put it to good use eh already with this01:42:21
So now yes I'm closing because01:42:23
well the transmission is already too extensive we01:42:24
already have a hour 4301:42:28
minutes here and one last message that01:42:30
I read from Steven S3 for the IES I01:42:33
recommend you do the review of all the01:42:36
high school topics you can take here,01:42:38
for example, my videos review01:42:39
arithmetic review algebra geometry01:42:42
trigonometry analytical geometry physics01:42:45
too eh Remember that there are a list01:42:47
of videos that are called exam-type questions,01:42:49
also remember that there are two01:42:52
playlists with01:42:54
physics courses, no one course is called a01:42:57
physics course for the fourth grade of the s in01:42:59
Spain, which was one that I produced back01:43:00
in 2010 for a portal01:43:02
called cybermatex in Spain that has01:43:04
theory, it has exercises, it has examples and01:43:07
there is another one called the physics course01:43:09
for the first grade of high school in01:43:10
Spain that is also at your service, that01:43:12
is, there are almost there, there are more than 200 videos01:43:15
For you who are here on my channel01:43:17
in these playlists, be careful, they are01:43:19
for high school, it01:43:21
is not University physics and I01:43:23
apologize for the university students but I am01:43:25
very sorry for not meeting your expectations01:43:29
But these videos are for high school,01:43:31
they are for young people who are still in01:43:33
school in the school in the high school01:43:35
in the high school whatever you want01:43:38
to call it that is in their stage before the01:43:40
university Yes when they are seeing those01:43:43
topics for the first time So01:43:45
for these kids there they have at their01:43:47
command everything is01:43:49
good content Well now My throat is01:43:51
going to burst from talking so much,01:43:54
excuse me, it's time. So to01:43:56
finish the transmission, I thank you01:43:59
very much for your company. For this time,01:44:02
for having accompanied me. Well, in that01:44:04
transmission, a little long, but you know,01:44:06
here is the video at your service. About01:44:08
this, the electrical circuits,01:44:11
remember to be aware of my networks.01:44:13
Here in the description of the video, I01:44:14
leave you the links to Facebook, Twitter,01:44:16
Instagram, so that you don't miss the01:44:20
next videos, the following01:44:22
broadcasts, which little by little I01:44:23
will tell you about, because what I know about. try01:44:25
okay remember to leave me your comments01:44:28
subscribe to the Channel uh I also01:44:30
invite you to do it01:44:32
Publicly to be able to read them more01:44:34
easily Yes because I filter01:44:36
the comments and I pay attention to01:44:38
those public subscribers to be01:44:41
able to uh that way attend to your01:44:44
comments and messages okay Well01:44:46
thank you again for your attention and we01:44:48
will see you next time take care of yourselves01:44:51
and I send you a big hug from01:44:53
Colombia that you are very well01:44:56
thank you and we will see you then01:44:58
next timeDescription:
En este video te explico la teoría básica de los circuitos eléctricos y cómo resolver tres situaciones: con resistencias conectadas en serie, en paralelo y mixto. Contenido 0:00 Saludos e información inicial 5:32 Explicación del tema 1:28:44 Atención a mensajes del chat y despedida Si consideras que estos videos han sido útiles para ti y deseas apoyarme, puedes hacerlo aquí: https://www.paypal.com/paypalme/julioprofenet Te invito a seguirme en redes sociales: 🔵 Facebook: https://www.facebook.com/unsupportedbrowser 🟣 Instagram: https://www.facebook.com/unsupportedbrowser ⚫ X: https://twitter.com/julioprofenet También te invito a visitar mi página web https://julioprofe.net/ para que consultes todos mis videos (organizados por categorías y temas) y los documentos que he producido, en la sección https://julioprofe.net/documentos/ ¡Que tengas éxito en tus actividades académicas! #julioprofe
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