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фрдз

32-14

00:00:01

let's write down what we've been given we've been given a work function

00:00:04

of 3.75 electron-volts let's convert

00:00:07

to units of si joule one electron-volt

00:00:10

is one point six tenths ten

00:00:12

minus 19 jul

00:00:14

if you don't remember this information

00:00:16

there are references at the beginning the test

00:00:18

was at the beginning essentially means multiply by

00:00:21

16 by 10 minus 19 and get 6 by 10

00:00:28

minus 19 powers of joules wavelength

00:00:33

denoted by Linda is 0.3 micrometers

00:00:37

converted to meters micro is 10 minutes 6

00:00:41

0.3 by 10 minus 6 or you can write 3

00:00:45

by 10 minus 7 meters like this d2 and a half

00:00:51

millimeter is also converted into a meter 2.5 by

00:00:54

10 minus 3 meters and we need to find

00:00:56

the intensity of the retarding field and the

00:01:01

intensity of the retarding field we

00:01:04

can find

00:01:05

if we know the retarding

00:01:07

voltage

00:01:08

and we will find the retarding voltage

00:01:10

using the Einstein equation for

00:01:12

the photoelectric effect,

00:01:14

recall the Einstein equation for the

00:01:19

photoelectric effect in the most general form, I usually

00:01:25

write it this way:

00:01:26

the energy of photons incident on a metal is equal to the

00:01:30

sum of the work function of electrons from

00:01:32

the metal and the maximum kinetic

00:01:35

energy of photoelectrons,

00:01:38

so in this case we express the energy of a photon

00:01:43

in terms of wavelength, the energy of a photon

00:01:50

is Linda I h Planck's constant c

00:01:53

speed of light in vacuum

00:01:55

a This is exactly the maximum kinetic

00:01:58

energy of photoelectrons, let's connect the

00:02:03

retarding voltage of

00:02:06

photoelectrons

00:02:08

and the maximum kinetic energy, this is the

00:02:14

elementary charge multiplied by the

00:02:17

retarding or blocking voltage,

00:02:19

this formula is ready in the codifier and does

00:02:21

not need to be displayed,

00:02:23

so you can depict here a failed

00:02:26

metal plate, here is a

00:02:29

retarding electric field

00:02:31

perpendicular to this plate so works

00:02:35

photo the electron flew out but it is obvious that it

00:02:37

will fly away to the maximum distance look for

00:02:40

the plates if its initial speed is

00:02:42

perpendicular to the plate directed by

00:02:44

the boulier then it will fly until it

00:02:46

stops until all its kinetic

00:02:49

energy is spent on work

00:02:52

against the field forces and we know this

00:02:58

distance is the maximum distance

00:03:00

by which the electron moves away and

00:03:02

move away to the maximum distance when

00:03:05

moving along the line e, this is what we have, and since

00:03:09

the field is uniform, then we can connect the

00:03:11

voltage between things.

00:03:13

well, or there is a potential difference, then in

00:03:16

this case it is the same thing, we can

00:03:22

relate the voltage between these points is the

00:03:25

same in magnitude to what and the

00:03:28

potential difference with the tension and

00:03:31

distance dtk we will write in a homogeneous

00:03:36

field

00:03:43

delaying or blocking this

00:03:46

same voltage y this and multiply by d the

00:03:57

field strength by the distance along the

00:03:59

line of intensity, all counted out, we

00:04:03

get an expression for the intensity, this

00:04:06

retarding voltage must be divided or

00:04:11

we can write that this is the maximum

00:04:15

kinetic energy of photoelectrons

00:04:17

divided by e

00:04:21

divided by i and divided by yes a

00:04:24

the maximum kinetic energy of

00:04:26

photoelectrons can be express through the

00:04:30

Stein equations this photon energy hc

00:04:33

zero to minus work function and all this on

00:04:38

e and you need to

00:04:41

substitute the numbers and calculate the constants

00:04:44

if you forgot them from the reference

00:04:46

materials at the beginning of the test, this at the beginning of the

00:04:48

manual is as much as 6 and 6 by 10 to the minus thirty-

00:04:54

fourth power c3 by ten to the eighth

00:05:00

wavelength according to the condition three to ten to

00:05:03

minus seventh

00:05:05

work function 6 to 10 to minus 19

00:05:09

elementary charge 16 to 10 minus 19 Dec

00:05:14

2 from half to 10 to minus 3 then I

00:05:19

calculated by the way, don’t be lazy, check

00:05:22

and I got 150 since all the units

00:05:27

were all that voltage turned out to be

00:05:29

units of

00:05:30

150 volts per meter, so we will write in the answer the

00:05:34

answer with e 150 volts per meter

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