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Teorema de Pitágoras

1:43

Verificar se o triângulo é retângulo Exercício 01

5:30

Calcular a medida de X no triângulo Exercício 02

16:44

Descobrir a medida da diagonal do quadrado Exercício 03

20:26

Determinar altura no triângulo Exercício 04

24:09

Descobrir o valor de X Exercício 05

$PROBABILIDADE \Prof. Gis/$

PROBABILIDADE \Prof. Gis/

Channel: Gis com Giz Matemática

Доказательство тригонометрических тождеств Пифагора

Доказательство тригонометрических тождеств Пифагора

Channel: MateFacil

Teorema de Pitágoras demostración

Teorema de Pitágoras demostración

Channel: fq-experimentos

23. Equation with complex and conjugated numbers

23. Equation with complex and conjugated numbers

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SIMETRIA

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You know that to learn mathematics

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you need to practice doing the

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exercises and I brought here exercises

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on Pythagoras' theorem for you to

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practice Remember the concepts And

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ace your activities and you're already

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asking, right? I can see your face from here it

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says where I use the theorem of

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Pythagoras in my life

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Pythagoras theorem it is still used today in

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civil constructions in Urbanism in

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architecture in physics and you know that

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these days I used the concept of

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Pythagoras' theorem in my daily life

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without knowing that I was going to use it and I went there

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and I used it like oh, I'm going to show you

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so I was walking down the street in the

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city and you know that

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blocks are like this, right,

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square shape, so I was right here, oh It's

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true, people, I'm not making it up, I was

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right here like this, right, and I I had to get

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here, which was the supermarket, which was

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on this other corner at the top, so instead

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of I came here, just walking here and

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then walking here, then I did it, it was a piece of

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land that had a lane here

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in the middle, I crossed over Here, I

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ended up using the Pythagorean theorem,

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here, shorten the path instead of

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walking along the sides. I already went there and

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walked over the hypotenuse. Here's an

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example, haven't you walked on terrain

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like that, instead of turning around, cut the

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path? You haven't done that already, right? So

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we can remember here an example of the

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Pythagorean theorem and see one thing

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when I talk about the Pythagorean theorem,

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it always happens in triangles that

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are right angles, it's not in any triangle that the

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Pythagorean concept applies and always in a triangle that is

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rectangular, take a look at this

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first example, the sides of a

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triangle measure 16, 30 and 34. So let's

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simulate here that I have a triangle.

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I'm going to do the simulation that my

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triangle is a right triangle and

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these sides measure 16

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30 and the longest side in this case would be

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the hypotenuse if it is a right triangle

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it would be 34 but the exercise asks check

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if this triangle with these measurements

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given here let's check if this

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triangle is a right triangle let's check it

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from here is it a rectangular because

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I can give you measurements of sides

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like this and the triangle does not form when

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you make the drawing, for example with the

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ruler the triangle is not a

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right triangle to be a

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90º right triangle here it is and how am I going to

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do this check you are

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asking, right? Enough talking and

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how do you check? So you will

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think like this, you will take the side

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here, this side which is the smallest, will be

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squared and will be added to this other

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side which is the other side, also

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smaller, squared very well. the sum of the

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squares of these two sides here that

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we are assuming is a

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right triangle so the sum of these sides here

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squared has to be equal to

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this side here also

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squared OK then just make ours here

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our perfect squares 16 which

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means 16 x 16 which will result in

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256 plus 30 to the power which is 30 x 30 which will

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be 900 and here 34 x 34 let's go I

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don't remember off the top of my head How much is 34 x 34 4

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x 4 16 which will be 1 4 x 3 12 12 3

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do it right away

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now by adding here 256 with 900 we

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will find

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1156 So you saw that this sum here the

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result was equal to the side here which

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would be the longest side of the Triangle

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squared the equality was verified

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this is true When it happens So, this is

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a

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right-angled triangle, that's why I was saying one

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side at that time, because when I

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have a right-angled triangle that I

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'm applying Pythagoras' theorem to,

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I do the side squared,

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plus the other side squared

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and this result has to be equal to the

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hypotenuse which is the longest side also

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squared it would be the formula would be

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the formula would be the Pythagorean theorem the

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formula of what we put applies to the

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production theorem are you paying attention in

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class so if here it were different

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the result here arrived here it was

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pretend 1.00 and here

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1556 so what does that mean this result

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was false, right the equality was false it

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means that the triangle referred to here with

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these measurements it is not a triangle it

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was not it would not be a right triangle

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beauty it gave to understand, so to

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carry out this verification, which is certainly

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there, one of the first activities

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when talking about

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Pythagoras' Theorem is to check whether the

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triangle is right-angled or not, ok Let's go

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to the second exercise, folks, look at

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question two, very simple, calculate the

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measurement

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unknown, come on,

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tell me what Pythagoras' theorem really is,

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I want to see if you paid

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attention to what I said in the

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previous exercise, I didn't write it like that, right?

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I'm going to write here, one side

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squared plus the other side

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squared, I'm abbreviating it

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here, okay, it's not cat, it's not cat cat, it's

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from side, okay And this sum will have to

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result in the

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hypotenuse also squared Ah,

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but you're saying that your

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teacher does the opposite he starts

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writing So let's write here in the

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corner he starts saying that the

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hypotenuse squared is equal

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to the side squared plus side

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squared that's how your teacher

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starts either one will

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work I either start by doing the sum

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of the sides of the squares of the sides or

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I start with the hypotenuse, okay, let's

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do it like this, I think most of

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you do it this way here two cats

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equal to o there two G has a production body, you

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're talking about it, but you like to invent my

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God to memorize, right, production does this

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to memorize cat squared plus cat

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squared gives the hippopotamus squared

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but let's go, people starting how do

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I identify chalk I still don't know how

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I identify who the hypotenuse is

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In a right triangle the hypotenuse is the

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longest side Or the one that is

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facing the 90º angle the side that is

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facing the 90º angle is the

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hypotenuse So it is here which is

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our x So let's go x qu equal to the

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other two that What remains are legs and

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which one do you start with either of the

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two you can choose let's go 28

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what plus the other side 21 a square

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because see here if you started with

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21 what is 28 A what after the addition it has

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the commutative property, right? It's a

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problem to change places, so it will

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work out, so continuing there you need

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to do 28 to the power, either you do

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mental calculation or you go to the corner of the

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notebook and you do 28 and don't get

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confused, then 28 is not 28 x 2

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no it's not 56 it's 28 x 28 let's see 8 x 8

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64 goes 6 8 x 2 16 16 with 6 it's 22 2 x 8

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16 goes 1 2 x 2 4 5 now I'm going to

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add it here and it will be 4 8 and 7 so

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here I will find

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784 + 21 that 21 x 21 o 1 x 1 1 1 x 2 2 2

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x 1 2 2 x 2 4 it will be 1 2 + 2 4 and here

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4

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441 Ok

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441 then you will add it First it will be

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x qu =

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784 +

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441 you do the calculations like this

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or you do mental calculations how

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do you do it so here it will be 5 8

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+ 4 are 12 which goes 1 7 + 1 8 8 with 4 12

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12225 well now let's see that to

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finish this exercise I need

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to find What number can I

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square that gives

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1225 and Here we will only find an

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But tell

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me, there is a value of one, there is a

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measure of a negative side, no, so that's

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why the answer is just a

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positive number and then you can also think about

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taking the square root, which would be the

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inverse operation to the potentiation, which is the

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root. square when the exponent is two

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you do the square root So you

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would need to find out the square root

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of

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12225 which means what the

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square root what number multiplied by

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itself which gives 1225 who knows let's go

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already know that it ends in five right

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because here, it's finished, it's 25, I think it

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ends in five, so you could

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do this type of square root calculation,

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if you don't know, by

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trial and error you could do it Oh,

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I know it ends in five, let's try

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25 to see if it works. If you do

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25 x 25 you will find 625 oh it is much

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more than 25 Oh so let's go 35

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35

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5 12 2

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and 1 12225 So this means that the x here

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in our question will be equal to 15

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cm Look guys, so I did all this

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here applying the Pythagorean theorem

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ahis but I could have done using the

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Pythagorean triplet what the triplet is

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Pythagorean for you who are asking

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because when the theorem was discovered,

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right, I'm going to delete all the calculations Look, it

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was developed, it was developed

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from a triangle with sides 3, 4 and

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5, just like I already have the demonstration,

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a class with the demonstration of this

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theorem I will leave the link for you in the

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description so if you take, for

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example, a triangle ulo that has

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measures like 3 4 and 5 if you think about

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this triangle here which was what gave

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rise to the Pythagorean theorem ó from 3

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to 21 it was x 7 4 to 28 was x 7 and 5

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to get to this x here I have to

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do 5 x 7 and 5 x 7 it's not 15 that I

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had put here right you must be there

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desperate screaming you wrote it

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wrong you wrote it wrong it's 35 a

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answer right people, production has already shouted that it's

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also time I wrote it wrong I

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said in a little while I'll fix it I thought in

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my head I'll fix it now Calm down

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then it's 35 Congratulations to you, you know

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why I did that to see if you're

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paying attention, of course We do

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this wrong here to see if your student is

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producing everything paying attention, right?

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So you could have done it using the

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Pythagorean teram or developed it here

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using this proportion that I discovered.

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by the

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proportion we prefer to do it by the

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theorem Let's go to the next one here, there is a

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square root now, in the hypotenuse

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Remembering that the hypotenuse is that side

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facing the right angle, an angle

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of 90º So what will this

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hypotenuse look like, which is ra qu 29

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squared

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equals squared + squared which is x

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qu

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How much is √29 raised squared from the

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properties of radiciation we have

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that every number that is

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squared I can make a

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simplification with its index And then leave

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the radical out only 29 is left, so

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every time you come across a

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square root raised to the square, it is the

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number itself that is in here, the

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result is equal to 5 or

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25 + x, which you can see that this guy here is

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different from the one here, right there, it was ready

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now. the x of the isolated because I have an

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equation to solve here, isn't it Guys,

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I have to find out what the value of x is

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and to find out the value of

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- 25 oh, I moved there like

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multiplication by -1 I'll do it so you can

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see how 29 - 25 will be ig a

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4 4 = x so to finish the exercise

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what number do I square that

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gives qu or you go there and take ra qu 4 and

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you find that ra qu 4 will be 2

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because I can't put here the

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plus or minus of also because there is no

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negative side, ok for you that here in this

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place here I preferred to

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move the X there o So you It arrived

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like -

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it will stay there, arrive in the same place, x =

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4, so x will be equal to 2, just like

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we did here, okay, you managed to

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understand this exercise here, just to

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do it for the proportion one, it wouldn't

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be as cool but as practical as

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this first one here so let's practice

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both ways and the letter C Look at the letter c

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do it first then come check

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with me so I already have the hypotenuse here

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So it's going to be

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square will be root Quad 8

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square plus ra Quad 8 which is the other

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side squared here it's easy, right people,

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so it will be x qu = ra 8 which if you

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did it would be 8 x 8 would give ra qu 64 isn't it

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Look, mark then ra qu 8 which would be ra 8

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= 16, how simple is that, huh, so it's

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going to be x = ra qu 16, you know who

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's good with the square root Tell me

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what the square root of 16 is, it's going to be 4

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because 4 x 4 16 so here our

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hypotenuse measures 4 perfect everyone, how are you?

00:16:42

Next exercise in the

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TRS question, guys, look, what is the

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diagonal measurement of a square with sides

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measuring 2 cm each? Of course, my

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drawing here is representative, right? My

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square that I brought here? So this

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square is 2 cm. each side I need to

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find out the measure of its diagonal the

00:17:06

diagonal is that segment like this, right,

00:17:09

that we talk about, right, that

00:17:10

crosses like this, right, people, so here, in

00:17:13

fact, the definition of diagonal is that

00:17:15

straight line segment that connects one vertex to

00:17:18

another vertex its opposite vertex in the

00:17:21

case of a square here, okay, so

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here I have the diagonal, ok here, as it

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is a square, we have the angle of 90º

00:17:31

And just calculate here now then apply

00:17:34

Pythagoras' theorem here is two which is the

00:17:36

same measurement here let's go then

00:17:38

Pythagoras' theorem I deleted it from here

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but do you remember that it is hypotenuse

00:17:43

squared in our case

00:17:45

our hypotenuse referring to the diagonal

00:17:48

So it will be D squared

00:17:50

equals equal to the side squared So

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it will be 2 plus the other the side

00:17:59

squared Ok so here it will be diagonal

00:18:03

squared equal to 2 qu 4 + 2 qu 4 so

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diagonal squared will be equal to 8

00:18:13

so now to know the value of the

00:18:15

Diagonal I take the inverse operation which

00:18:18

is the square root so ra 8 The square

00:18:22

of 8 is not the exact value, right? Because

00:18:25

there is no number that multiplies by

00:18:27

itself to give eight. So in this case, we

00:18:29

can take the approximate root or

00:18:32

decompose this eight into

00:18:34

prime factors, eight. You can divide

00:18:37

by two, which gives 4 which can be divided

00:18:40

by two which gives 2 by 2 which gives 1 now

00:18:43

how here it is a square root

00:18:46

index 2 I group it here in twos

00:18:48

oh so here it would be 2 to the power of 2 oh

00:18:52

what do I do now so in Instead of

00:18:54

writing eight, I write its

00:18:56

factored form, which is 2 to the square times

00:19:01

this 2 here, and then remember that I

00:19:04

already talked about the properties of

00:19:06

radiciation, I can take here then the

00:19:10

radicand number that has its exponent

00:19:12

equal to index it comes out outside the root

00:19:14

so this one comes out outside the root This one

00:19:17

as it has the exponent one which is different

00:19:19

from the index it remains in the root so I

00:19:22

can make the simplified answer right

00:19:26

through decomp position as being

00:19:30

by x they are so used to x as

00:19:33

the measurement of the Diagonal being equal to 2 ra qu of

00:19:36

2 cm and here comes That case for those of you who have

00:19:41

already seen my class on the diagonal of

00:19:43

a square Every time you have the

00:19:45

diagonal of the square to calculate you

00:19:48

will always calculate the value on the side Ó the

00:19:50

side is not two look here the side is from Ó

00:19:52

the value of the side multiplied by the root

00:19:55

qu2 so if I had a square that

00:19:57

told me 5 here so I could calculate its

00:20:01

diagonal the result would be 5 √2 just

00:20:05

do it like this then do it straight away if you

00:20:07

remember the Formula o mark it there o every

00:20:09

time you calculate the diagonal of a

00:20:11

square the formula would be L which is the

00:20:14

measurement of the side multiplied by the

00:20:16

square root 2 it's a little shortcut for

00:20:19

you but don't worry forgot that,

00:20:21

apply Pythagoras' theorem and everything will

00:20:23

work out ok. Next exercise here is

00:20:25

a contextualized question now, right?

00:20:39

perpendicular to the ground So let's

00:20:41

imagine like this, there's a wall, a wall,

00:20:43

a wall in your house, let's do it

00:20:45

here, here, the roof part of the house,

00:20:48

here's the wall, right, noa, but let me

00:20:50

draw the rest, everything, this wall, it

00:20:54

's perpendicular to the ground, that is, it forms a

00:20:57

90º angle with the ground, right? And this ladder

00:21:00

is here supported here on this wall, oh the

00:21:02

ladder here, right here, the ladder that is

00:21:05

supported on this wall and he already said that

00:21:08

this ladder is 10 m long, oh 10

00:21:11

m long, knowing that the foot of the

00:21:14

ladder is 6 m away from the base of the

00:21:18

wall, this other information is already

00:21:20

valid, the foot of the ladder is here

00:21:23

at a distance of 6 m from our

00:21:30

wall, determine the height in meters

00:21:33

reached by the ladder What's up, people? In what

00:21:37

everyday situation is

00:21:38

this used here? Fire Department, right, when you're going to

00:21:41

get someone from the fire, stretch the

00:21:44

stretcher, I think that's how you say it, right,

00:21:46

put the ladder, right? It's a situation where someone is

00:21:49

going to get something else from the

00:21:51

basement. put the ladder, so you can

00:21:53

think about the Pythagorean theorem in this

00:21:55

everyday situation, so let's go, you can

00:21:58

see there a right triangle,

00:22:00

you can see here, the

00:22:02

right triangle is here, our 10 is the

00:22:06

hypotenuse, the six is a leg and the height

00:22:09

here from our wall that the amount that the

00:22:12

ladder reached is x apply

00:22:15

Pythagoras theorem starting with the hypotenuse you

00:22:18

can or starting with the side let's

00:22:20

start with the hypotenuse, right

00:22:23

10 Quad which is hypotenuse squared

00:22:26

equals CET

00:22:30

squared plus the other side squared

00:22:34

Oh Mark it for those who forgot

00:22:36

hypotenuse squared equals leg squared

00:22:40

plus leg

00:22:45

squared cat cat squared plus cat

00:22:48

squared hippopotamus squared the

00:22:50

definition of production here so I don't

00:22:52

forget Pythagoras' theorem okay guys,

00:22:55

let's go here I can do it 10 which is 100

00:22:58

which is 10 x 10 = I

00:23:17

'm going to take this 36 and I'm going to put it there on the

00:23:20

first member with 100. So it's going to be

00:23:22

100 - 36 which is iG

00:23:39

the

00:23:42

inverse operation here D of the

00:23:44

square of the power with exponent 2 is

00:23:47

the square root I take the square ra 64

00:23:51

and the Quad ra 64 will be equal to 8 So

00:23:56

that means that this one reached a height

00:23:59

of 8 m Look, guys, a situation easy

00:24:03

to apply, right, you managed to understand

00:24:05

this one and now let's go to the last

00:24:08

question Look at question 5 now we have

00:24:11

x + 3 x + 6 there is X everywhere here

00:24:14

how are we going to solve it to

00:24:16

find out the value of

00:24:18

right triangle what does it do there

00:24:21

Pythagoras theorem production you're already

00:24:23

complaining that it's difficult no it's not you're

00:24:25

not saying it's also not the same production it

00:24:27

's difficult no I'll explain

00:24:30

Calm down you're asking about magic that it

00:24:32

does so come and see me I'm going to

00:24:33

explain the Pythagorean theorem

00:24:35

hypotenuse squared whoever is hypotenuses

00:24:39

the longest side of the triangle which would be x +

00:24:41

6 So it's going to be x + 6 what do you

00:24:47

have to do to put the parentheses ok

00:24:49

because I'm going to elevate both terms here

00:24:51

squared equals the side x + 3 a

00:24:58

squared so also look at the importance

00:25:00

of putting the

00:25:01

parentheses plus the other side which is just

00:25:13

here is a remarkable product

00:25:16

Guys, what does x + 6 mean x +

00:25:20

6 which is the same thing as x + 6 x x if

00:25:28

here you can

00:25:30

develop this remarkable product

00:25:33

using our standard that we

00:25:35

already have and I have the class explaining

00:25:38

everything about notable products or you go

00:25:41

there and do the shower,

00:25:43

actually, right, so it will be like this x x x x qu x

00:25:53

x 6 6x now 6 x

00:26:11

I'm going to group the terms that are similar 6 + 6 here as the two t

00:26:32

12x + 36 and equal Let's go to the next x

00:26:38

+ 3 raised Quad or you do it using the

00:26:41

shower head or you do it using the

00:26:45

standard, the standard for those who don't know would be

00:26:48

the square of the first term or the square of the

00:26:51

first term plus two times the 6 which

00:26:55

gives 12 12 x x 12 x plus the square of the

00:26:59

second term, then using the

00:27:02

direct formula, the square of this guy here

00:27:16

Now let's go through the shower x + 3 x x x

00:27:45

here you can see So

00:27:47

you can do it using the standard And then we just had to

00:27:50

copy this squared x here My God,

00:27:53

how many counts now we need

00:27:55

to group the terms that are similar

00:27:58

guys Have you already copied this from here in the shower

00:28:00

that I'm going to need to delete because I don't

00:28:01

have enough pictures here to do

00:28:03

all these calculations, otherwise you would have to do it

00:28:05

like those classrooms that go around

00:28:06

the boards like that, I

00:28:09

already had people when I was studying, the

00:28:11

teacher would go to a board, there was

00:28:14

a room, I remember to this day there was a

00:28:16

room that was in front with a frame and the

00:28:18

side with a frame then it passed through this

00:28:20

frame and passed along the side I also said oh

00:28:22

my God so let's go, what is it possible to

00:28:24

group here, you realize that there is

00:28:31

We can take what we pass on,

00:28:33

everyone here to the first member here,

00:28:35

want to see what it will look like, x

00:28:38

qu +

00:28:40

12x + 36, oh this x which I can now combine

00:28:47

with this x which, right, it will be 2x which and I'm going to

00:28:52

throw it to first member which will

00:28:54

be Men 2x I did a little direct this one

00:28:58

I added 1 x qu here with x qu here which

00:29:02

gave 2 and I threw it to the first side as

00:29:04

- 2x

00:29:06

qu -

00:29:08

6x - 9 and then I leave the second side

00:29:11

Zero to apply here then a

00:29:13

quadratic equation in its

00:29:15

reduced form, what can I group

00:29:17

here, people, 1x what from here Where is it

00:29:23

here, - 2x what from here will be -

00:29:34

be +

00:29:37

6x and 36 here is 36 and -9 if I have

00:29:43

36 and I owe 9 it will be + 27 = 0 and I

00:29:49

now have a quadratic equation

00:29:52

to be solved in this quadratic equation

00:29:54

I can now take Who

00:29:58

Let's go and write the coefficients in this equation.

00:30:00

Who is the coefficient?

00:30:04

Tell me, let's see who is remembering

00:30:05

the quadratic equation class,

00:30:08

people mix Pythagoras with the

00:30:10

quadratic equation. Yes, there are a lot of things here for

00:30:12

you to remember, a is men1. which is the

00:30:16

guy who is on the side of

00:30:32

second degree by product sound or by

00:30:33

mask I do it using the mask solving formula

00:30:36

which seems to be common for

00:30:38

everyone to understand so let's go

00:30:40

and calculate who is the discriminant the

00:30:42

delta B

00:30:45

qu - 4 x a x c so Delta will be equal to

00:30:52

B qu Where is b 6 6

00:30:55

qu minus 4 times a which is

00:31:00

-1 times c which is

00:31:04

27 so it will be Delta = 6 qu

00:31:09

36 4 now I do the multiplication right 4

00:31:13

x 1 4 4 X 27 27 with 27 54 54 54

00:31:19

108 then minus with minus plus I go

00:31:23

find then that the delta will be

00:31:26

144 adding here very well now

00:31:29

continuing x = a - b for those who

00:31:34

forgot the solving formula here,

00:31:36

more or less Delta divided by two

00:31:39

times a I like to separate the

00:31:42

discriminant here to make it better for the

00:31:43

student understand but you can do it together

00:31:46

so it will be x = - b Where is the b the b is 6

00:31:50

so it will be

00:31:51

-6 more or less the square root of the

00:31:54

Delta that is the square root of 140 4

00:31:57

how much is ra qu 144 who knows it is

00:32:02

12 divided by Du vees o a o a is -1 it

00:32:07

's not so it's twice o-1 which will be

00:32:09

-2 So now I'm going to find an X which is

00:32:14

going to be -6 + 12 div by

00:32:19

-2 I'm going to find another x which is going to

00:32:24

be -6 - 12 divo by -2 oh one is more here

00:32:29

in the middle the other is less And then I can

00:32:32

do it here oh if I owe six and I have

00:32:34

12 I get 6 right and divide 6 by -2

00:32:38

6 by 2 gives 3 so here The result will

00:32:41

be -3 very well here I owe six I

00:32:46

owe 12 I combine the two debts I owe

00:32:50

18 is -18 oh I'll write it here you can see

00:32:54

production divided by -2 minus with minus

00:32:58

will give plus 18 by 2 here you will find

00:33:00

the result of 9 Okay now we're going to

00:33:03

analyze it could be any of the Two

00:33:06

answers no right people because I

00:33:08

can't say the x here It's worth -3 people oh

00:33:10

this side measures -3 no then The negative

00:33:14

cannot be used here so the

00:33:16

value of it's going to be 9, so here it's going to

00:33:20

be 9, this side is going to be 9, this side is TR,

00:33:26

which is going to be

00:33:27

and this side is 9 plus 6, which is going to be 15, that

00:33:31

's it, the question is solved,

00:33:33

we found the value of x and we went further and

00:33:36

found the sides of our the measurements

00:33:38

of the sides of the triangle Say, did you find

00:33:41

this question difficult, whether production or

00:33:42

not production, said that you found

00:33:44

this question difficult but do it calmly

00:33:48

and you can practice, then pause the

00:33:51

video, practice and then you can

00:33:53

check Where are you going wrong, where is

00:33:55

your difficulty? and another thing Did you

00:33:57

see how many classes are involved to

00:33:59

solve a type of exercise like this, that's why

00:34:01

I say that math is

00:34:02

cumulative, miss a class back then

00:34:06

you'll have difficulty up

00:34:07

front Dev will say he doesn't know

00:34:09

math Because you lost the one there

00:34:11

then means that you have to

00:34:12

attend another class,

00:34:14

previous concepts and how you do it, you need

00:34:16

a class on the channel. What are you going to

00:34:18

do, type the name of the content and

00:34:22

chalk in front of it, get that

00:34:24

wonderful class for you to master So,

00:34:27

try your activity and give it a like and don't

00:34:29

forget to subscribe to the channel and I

00:34:31

'll see you in the next class

00:34:35

bye

Description:

✅Nesse você vai ver a resolução de exercícios sobre o TEOREMA DE PITÁGORAS. Matemática com a Gis =============================================================================== 🏠 Loja da Gis: https://giscomgiz.com.br//loja/ 📚Cursos indicados pela Gis: https://giscomgiz.com.br/cursos/ 🌎Site da Gis: www.giscomgiz.com.br ✍️Pratique TABUADA com as tabelas da TABUADA da Gis: https://giscomgiz.com.br/cursos/tabuada-da-multiplicacao-tabelas/ =============================================================================== 💢Compartilhe esse vídeo: https://www.youtube.com/watch?v=tJwdgWdFvGg 🔻🔻 Você pode gostar desses vídeos também: 🔻🔻 TEOREMA DE PITÁGORAS \Prof. Gis/: https://www.youtube.com/watch?v=RxfPjqXx-g0 TEOREMA DE PITÁGORAS | EXERCICIOS SOBRE TEOREMA DE PITÁGORAS | \Prof. Gis/: https://www.youtube.com/watch?v=YBkhviGTcnM RELAÇÕES MÉTRICAS NO TRIÂNGULO RETÂNGULO \Prof. Gis/: https://www.youtube.com/watch?v=mFszQZAke7o DIAGONAL DO QUADRADO |TEOREMA DE PITÁGORAS | \Prof. Gis/: https://www.youtube.com/watch?v=yb7hoDm_ZbQ ALTURA DE UM TRIÂNGULO EQUILÁTERO | TEOREMA DE PITÁGORAS | \Prof. Gis/: https://www.youtube.com/watch?v=Dfvtyq9MtHY PRODUTOS NOTÁVEIS: https://www.youtube.com/watch?v=fk8CmDJxWC0&list=PLGyv8aUrOlzA2vqp8-1f-s5mMiBK_ifHl EQUAÇÃO DO 2º GRAU - https://www.youtube.com/playlist?list=PLGyv8aUrOlzBk-ctqa9e7jBlLxnqGcrho Capítulos: 00:00 Teorema de Pitágoras 01:43 Verificar se o triângulo é retângulo Exercício 01 05:30 Calcular a medida de X no triângulo Exercício 02 16:44 Descobrir a medida da diagonal do quadrado Exercício 03 20:26 Determinar altura no triângulo Exercício 04 24:09 Descobrir o valor de X Exercício 05 Bons estudos 💜 🔻⬇ Conecte-se comigo ⬇🔻 💻 Meu Site: https://giscomgiz.com.br 👉 Inscreva-se no Canal: https:// https://www.youtube.com/c/GiscomGiz 📲 https://www.tiktok.com/@giscomgizmatematica 📲 Instagram: https://www.facebook.com/unsupportedbrowser 🚀Roblox: https://www.roblox.com/users/3054831084/profile Grande abraço, Gis Bezerra.

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